将Apache Spark Scala代码转换为Python

Question

任何人都可以将这个非常简单的scala代码转换为python吗？

val words = Array("one", "two", "two", "three", "three", "three")
val wordPairsRDD = sc.parallelize(words).map(word => (word, 1))

val wordCountsWithGroup = wordPairsRDD
    .groupByKey()
    .map(t => (t._1, t._2.sum))
    .collect()

Answer 1

试试这个：

parentDirPath := ExtractFilePath(ExcludeTrailingPathDelimiter(thePath));

Answer 2

在python中进行两次翻译：

from operator import add
wordsList = ["one", "two", "two", "three", "three", "three"]
words = sc.parallelize(wordsList ).map(lambda l :(l,1)).reduceByKey(add).collect()
print words
words = sc.parallelize(wordsList ).map(lambda l : (l,1)).groupByKey().map(lambda t: (t[0], sum(t[1]))).collect()
print words

Answer 3

假设您已经定义了Spark上下文并准备好了：

if count >= xyz 

查看github示例repo：Python Examples