Question

我正在进行codecademy.com javascript课程，我的联系信息完成时遇到问题。它正在返回，但我收到一个错误，通知我它没有返回史蒂夫。我一直在绞尽脑汁这么多我无法直接看到......

链接如下 http://www.codecademy.com/courses/javascript-beginner-en-3bmfN/0/7

var friends = new Object();
friends.bill = new Object();
friends.steve = new Object();

friends.steve.firstName = "steve";
friends.steve.lastName = "jobs";
friends.steve.number = "317-222-3344";
friends.steve.address = ["one apple way","california","us"];

friends.bill.firstName = "bill";
friends.bill.lastName = "gates";
friends.bill.number = "327-332-3322";
friends.bill.address = ["one microsoft way","washington","us"];

var list = function (name){
    for(var key in name){
    console.log(friends[key]);
   }
};

var search = function(name){
    for(var key in friends){
    if(friends[key].firstName === name){
        console.log(key);
        return search;
     }
   }
};

search("bill");
search("steve");
list(friends);

Answer 1

您正在返回搜索功能。只需将其更改为您想要的内容即可。

return friends[key];

var friends = new Object();
friends.bill = new Object();
friends.steve = new Object();

friends.steve.firstName = "Steve";
friends.steve.lastName = "jobs";
friends.steve.number = "317-222-3344";
friends.steve.address = ["one apple way","california","us"];

friends.bill.firstName = "Bill";
friends.bill.lastName = "gates";
friends.bill.number = "327-332-3322";
friends.bill.address = ["one microsoft way","washington","us"];

var list = function (name){
    for(var key in name){
    console.log(friends[key]);
   }
};

var search = function(name){
    for(var key in friends){
    if(friends[key].firstName === name){
        var f = friends[key];
        console.log(f.firstName,f.lastName,f.number,f.address);
        return f;
     }
   }
};

search("bill");
search("Steve");

Answer 2

测试正在寻找区分大小写的名称，它首先查找“Steve”。将每个名字改为标题案例，你将通过。

联系信息列表未返回＆＃34;错误＆＃34;即使它正在返回信息

2 个答案: