Question

我正在编写一个问数学问题的脚本，我想知道，我将如何制作计时器？我想制作一个计时器，使用户有20秒的时间来回答，当时间到了，然后说：“抱歉，不正确。”我已经尝试记录问题的时间，然后从他们回答问题时减去它，然后如果它大于或等于20显示不正确，但它不起作用。任何帮助将不胜感激。

if op != '*': # != means 'not equal'
    r1 = random.randint (-1, 100) # Randomises a number from -1 to 100
    r2 = random.randint (-1, 100)
    answer = ops.get(op)(r1,r2)
    start = time.time()
    equ = int(input('Q{}: What is {} {} {}?\n'.format(q, r1, op, r2)))
    end = time.time()
    if end - start >= 20:
    print ("Sorry you took too long to answer.")
    elif answer.upper() = 'FRIDAY':
    print 'Correct, today is {}'.format(answer)
else:
    r1 = random.randint(-1,12)
    r2 = random.randint(-1,12)
    answer = ops.get(op)(r1,r2)
    equ = int(input('Q{}: What is {} x {}?\n'.format(q, r1, r2)))
if equ == answer :
    score += 1
    print("Correct, Well done, your score is: " + str(score))
else:
    print("Incorrect, Sorry. Your score is: " + str(score))

Answer 1

您可以使用此类内容来查看是否需要超过20秒才能回答：

import time

start = time.time()
answer = raw_input('What day is it?: ')
end = time.time()

if end - start >= 20:
    print 'You took too long to answer'
elif answer.upper() == time.strftime('%A').upper():
    print 'Correct, today is {}'.format(answer)
else:
    print 'That's not correct, sorry'

编辑：我认为这适用于您要完成的任务。希望你接受这个并从中学习。

import time
import random
import operator 
ops = {'+':operator.add,
           '-':operator.sub,
           '*':operator.mul,
           '/':operator.truediv}
i = 1
while True:
    r1 = random.randint(-1,12)
    r2 = random.randint(-1,12)
    op = random.choice(list(ops.keys()))
    answer = ops.get(op)(r1,r2)

    start = time.time()
    equ = int(input('Q{}: What is {} {} {}?\n'.format(i, r1, op, r2)))
    end = time.time()

    if end - start >= 10:
        print('You took too long to answer')
    elif equ == answer:
        print('Correct!')
    else:
        print('Wrong')

    i += 1

如何在python中创建一个计时器

1 个答案: