Question

好的，所以我对python来说比较新，这可能很简单。但是，我很难过。到目前为止，我所拥有的代码遍历文本文件的每一行;读取每一行;在每一行中搜索某个字符串;如果找到该字符串，则提示用户改变行x行数，然后继续搜索这些行。我想要做的是创建一个字符串列表;让程序搜索每个字符串的每一行;如果找到一个字符串，则会发生与之前描述相同的字符串;然后，一旦创建了新行，程序将继续查看字符串的每一行，如果它找到另一行与其中一个字符串，它将覆盖一行x行。我已经尝试了一个＆＃39; for＃39;循环做到这一点，但到目前为止还没有成功。想法？

findArray1 = [find1,find2,find3]

#this is my initial attempt
with open(filename, 'r') as f:
        with open(filename+".BAK", 'w+') as newFile:
            for i,line in enumerate(f):
                if foundLine == 1:
                    foundLine += 1
                    newFile.write(line)
                elif (foundLine >= 2 and foundLine <=3):
                    number = float(input("Enter the overwrite string %swith: " %line))
                    splitLine = line.split('=')
                    newLine = "%s=%s\n" % (splitLine[0], number)
                    newFile.write(newLine)
                    foundLine += 1
                elif find4 in line:
                    foundLine = 1
                    newFile.write(line)
                elif find5 in line:
                    foundLine = 1
                    newFile.write(line)
                elif find6 in line:
                    foundLine = 1
                    newFile.write(line)    
                else:
                    newFile.write(line)

    os.remove(filename)

    os.rename(filename+".BAK", filename)

#idea for the loop instead of having all the elif and the else statements
else:
     for findLine in findArray1:
         for findLine in line:
             foundLine = 1
             newFile.write(line)
     newFile.write(line)

如何在搜索

0 个答案: