Question

有一个php代码，它通过对日期进行排序并选择数据来从数据库中获取数据。通过使用id来尊重并显示结果。

$mysqli=mysqli_connect('localhost','USname','Pass','DB');
                    //From Ajax 

             $id = trim($_POST["storedValue"]);

             //selact data from database based on id 

        $query ="SELECT * FROM Data WHERE  StudentID='$id' order by Date desc limit 1";
$result = mysqli_query($mysqli,$query)or die(mysqli_error());
$num_row = mysqli_num_rows($result);
            while($row=mysqli_fetch_array($result))
    {
 //fetched some id where respect to that data has to be displayed 
    $Fetch_id =$row[1];

    //From Ajax 
  $id = trim($_POST["storedValue"]);

      // Fetching data From database respect to $id "From Ajax " & Fetched data From database  i.e. "$Fetch_id"

       $query1 ="SELECT * FROM data WHERE  StudentID='$id' And Fetch_id='$Fetch_id' ";

$result1 = mysqli_query($mysqli,$query1)or die(mysqli_error());
$num_row1 = mysqli_num_rows($result1);

            while($row1=mysqli_fetch_array($result1))
    {



  // Display final result 
       echo 
       "<table >
       <tr>
       <td>".$row1[6]."<td/>
       <td>".$row1[4]."</td>
       <td>".$row1[5]."</td>
       </tr></table>" ;

    }

    }

EX：

数据库

 slno   Fetch_id  StudentID         date                   data1    data2     data3
  1      AB003      123     2015-10-12 00:00:00            abc3      456       258
  2      AB003      123     2015-10-10 00:00:00            abc3      456       258
  3      AB003      123     2015-10-09 00:00:00            abc3      456       258
  4      AB002      123     2015-10-08 00:00:00            abc2      456       258
  5      AB002      123     2015-10-05 00:00:00            abc2      456       258
  6      AB002      123     2015-10-04 00:00:00            abc2      456       258
  7      AB002      123     2015-10-03 00:00:00            abc2      456       258
  8      AB001      123     2015-10-02 00:00:00            abc1      456       258
  9      AB001      123     2015-10-01 00:00:00            abc1      456       258
  10     AB001      123     2015-09-04 00:00:00            abc1      456       258
  11     AB001      123     2015-09-03 00:00:00            abc1      456       258
  12     AB001      123     2015-09-02 00:00:00            abc1      456       258

结果：

第一次查询：仅供参考：StudentID＆＃34; 123＆＃34; 在DESC订单通过将日期和学生ID＆＃34; 123＆＃34;

的最新结果排序日期

即：

 AB003

第二次查询：对于Fetch_id：AB003和StudentID：123

显示结果

              data1     data2        data3
               abc3       456       258
               abc3       456       258
               abc3       456       258

期待最终结果应该跳过第一次重复的Fetch_id并选择Next Fetch_id

第一次查询：仅供参考：StudentID＆＃34; 123＆＃34; 显示结果 跳过AB003 ID，应选择AB002

 AB002

第二次查询：对于Fetch_id：AB002和StudentID：123

显示结果

     data1     data2    data3
     abc2       456       258
     abc2       456       258
     abc2       456       258
     abc2       456       258

PHP使用MySQLi和id

0 个答案: