Question

我的课程类似于：

@XmlRootElement
public class myObject{

    String name;
    String age;
    String value;

    public String getName() {
        return name;
    }

    @XmlElement
    public void setName(String name) {
        this.name = name;
    }

    public String getAge() {
        return age;
    }

    @XmlElement
    public void setAge(String age) {
        this.age = age;
    }

    public String getValue() {
        return value;
    }

    @XmlAttribute
    public void setValue(String value) {
        this.value = value;
    }

}

我希望生成一个类似于：

的xml文件

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<myObjects>
  <myObject value="34">
    <set varname="name" value="String"/>
    <set varname="age" value="String"/>
  </myObject>
  <myObject value="345">
    <set varname="name" value="String"/>
    <set varname="age" value="String"/>
  </myObject>
</myObjects>

如何调整我的类以生成所描述的XML？

我要问的重要一点是如何设置myObject以获得以下示例：

  <myObject value="34">
    <set varname="name" value="String"/>
    <set varname="age" value="String"/>
  </myObject>

我正在使用JAXB：

    myObject customer = new myObject();
    customer.setValue("100");
    customer.setName("mkyong");
    customer.setAge("29");

    ....fill my object here

    JAXBContext jaxbContext = JAXBContext.newInstance(myObject.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

    // output pretty printed
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    StringWriter writer = new StringWriter();
    jaxbMarshaller.marshal(customer, System.out);
    jaxbMarshaller.marshal(customer, new StreamResult(writer));

这就是我现在拥有的XML：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<myObject value="34">
    <age>String</age>
    <name>String</name>
</myObject>

谢谢！

Answer 1

您需要再创建一些JaxB对象

<强> MyObjects

@XmlRootElement(name="myObjects")
public class MyObjects {
    protected List<MyObject> myObject;

    public MyObjects(){
        setMyObject(new ArrayList<MyObject>());
    }

    public List<MyObject> getMyObject() {
        return this.myObject;
    }

    @XmlElement(name="myObject")
    public void setMyObject(List<MyObject> myObject) {
        this.myObject = myObject;
    }
}

<强>为MyObject

public class MyObject {
    String value;
    List<Set> set;

    public MyObject(){
        set = new ArrayList<Set>();
    }

    public List<Set> getSet() {
        return this.set;
    }

    @XmlElement
    public void setSet(List<Set> set) {
        this.set = set;
    }

    public String getValue() {
        return value;
    }

    @XmlAttribute
    public void setValue(String value) {
        this.value = value;
    }
}

设置

@XmlType(propOrder = { "varName", "value" }) public class Set { String varName; String value; public String getVarName() { return varName; } @XmlAttribute public void setVarName(String varName) { this.varName = varName; } public String getValue() { return value; } @XmlAttribute public void setValue(String value) { this.value = value; } }

测试我创建了一个你描述的对象并通过你的编组器
运行它
MyObjects mos = new MyObjects(); MyObject mo1 = new MyObject(); mo1.setValue("34"); Set set1 = new Set(); set1.setVarName("age"); set1.setValue("String"); mo1.getSet().add(set1); Set set2 = new Set(); set2.setVarName("name"); set2.setValue("String"); mo1.getSet().add(set2); mos.getMyObject().add(mo1); MyObject mo2 = new MyObject(); mo2.setValue("345"); Set set3 = new Set(); set3.setVarName("age"); set3.setValue("String"); mo2.getSet().add(set3); Set set4 = new Set(); set4.setVarName("name"); set4.setValue("String"); mo2.getSet().add(set4); mos.getMyObject().add(mo2);

输出看起来像这样

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <myObjects> <myObject value="34"> <set varName="age" value="String"/> <set varName="name" value="String"/> </myObject> <myObject value="345"> <set varName="age" value="String"/> <set varName="name" value="String"/> </myObject> </myObjects>

这就是你的目标

JAXB - 如何使用<set varname =“String”value =“name”“string2”=“”>元素从对象创建xml

1 个答案: