Question

我正在尝试在此页面上获取视频链接https://in.news.yahoo.com/video/jitendra-singh-visits-manipur-militants-051500244.html。我尝试了多种方式使用硒但没有运气。有人可以指出我做错了吗

driver = webdriver.Chrome()
def getVideoTrend(self, "https://in.news.yahoo.com/video/jitendra-singh-visits-manipur-militants-051500244.html"):
    driver.get(url)
    element = WebDriverWait(driver, 10).until(lambda driver: driver.find_elements_by_class_name('mediavideoplayervppca'))
    video_trend = []
    #s = driver.find_element_by_css_selector('video.yvp-html5-video') #this also does not help
    s = driver.find_elements_by_xpath('//*[@id="yui_3_9_1_1_1434089562443_964"]')
    print s
    print s.get_attribute('src')

请在Chrome中打开链接以查看页面元素

Answer 1

在该给定的网址中，您只有一个视频标记。所以你可以使用tagName获得src。

类似的东西：

    By byLocator = By.tagName("video");
    new WebDriverWait(driver, 20).until(ExpectedConditions
            .presenceOfElementLocated(byLocator));
    WebElement findElement = driver.findElement(byLocator);
    System.out.println("Src file : " + findElement.getAttribute("src"));

使用selenium从视频标签获取src

1 个答案: