搜索由音频识别生成的arrayList

时间:2015-06-12 08:00:47

标签: java android audio arraylist

我正在研究用户的音频并将其保存在arrayList中,然后搜索此数组列表以查看谷歌音频API生成的所需单词是否存在,以便我们可以执行操作。删除我想要的操作并用textview替换它只是为了查看它是否正常工作,音频识别是否正常工作,但我始终将textview文本作为停止。那么问题是什么?

package myfirstapp.myapps.me.voicerecognition;

import android.content.Intent;
import android.os.Bundle;
import android.speech.RecognizerIntent;
import android.support.v7.app.ActionBarActivity;
import android.view.View;
import android.widget.Button;
import android.widget.ListView;
import android.widget.ArrayAdapter;
import android.widget.TextView;
import java.util.ArrayList;

public class MainActivity extends ActionBarActivity implements View.OnClickListener {
    ListView lv;
    Button recBtn;
    static final int check = 1111;
    TextView tv;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        lv = (ListView) findViewById(R.id.lv);
        recBtn = (Button) findViewById(R.id.recBtn);
        tv = (TextView) findViewById(R.id.textView);
        recBtn.setOnClickListener(MainActivity.this);
    }

    public void onClick(View v) {
        Intent i = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
        i.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
        i.putExtra(RecognizerIntent.EXTRA_PROMPT, "Speak");
        startActivityForResult(i, check);
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (requestCode == check && resultCode == RESULT_OK) {
            ArrayList<String> results = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
            lv.setAdapter(new ArrayAdapter<String>(MainActivity.this, android.R.layout.simple_list_item_1, results));
            String s = "start";
            for (String string : results) {
//                if(string.matches("start"))
//                    tv.setText("Ok");
//                else
//                    tv.setText("No start");
//                }
                if (string.startsWith(s))
                    tv.setText("Start");
                else
                    tv.setText("Stop");
            }
            super.onActivityResult(requestCode, resultCode, data);

        }
    }

}

1 个答案:

答案 0 :(得分:2)

找到匹配项时不会从循环中断,所以除非匹配项位于列表的最后一个String中,否则文本视图将在末尾包含Stop。

您可能希望将其更改为:

       boolean match = false;
       for (String string : results) {
            if (string.startsWith(s)) {
                tv.setText("Start");
                match = true;
                break;
            }   
       }
       if (!match)
           tv.setText("Stop");