Question

我想查询下面的两个表，以获取新表中当前表中尚未包含名称或代码条目的行。

table current

name           code
japan          233
india          65
england        44


table new

name           code
japan          233
india          65
england-main   44
japan          2331
india          652
usa            1

在这个例子中它应该返回

name         code
usa          1

sql查询将归档此enter code here

Answer 1

SELECT name, code 
FROM new 
WHERE name NOT IN (SELECT DISTINCT name FROM current)
AND code NOT IN (SELECT DISTINCT code FROM current);

不知道你正在使用什么样的SQL，所以这个查询可能会有所不同或根本不起作用。

编辑后：此查询将检查当前表中是否存在名称和代码。但是，它不会检查它们是否在同一记录中。

Answer 2

SELECT name, code 
FROM new n
WHERE NOT EXISTS(SELECT * FROM current c 
                 WHERE c.name = n.name OR c.code = n.code)

Answer 3

select * from
(select 
    n.*,
    c.code as old_code
from 
    new as n left join 
    current as c on n.code = c.code) as T
where T.old_code is null

或者只是

select * from new as n where not exist (select 1 from current as c where c.code = n.code)

Answer 4

select * from new where name not in (select name from current) and code not in (select code from current);

可以在mysql中完成这个技巧

Answer 5

试试这个：

select * from new_table where name not in (select name from current_table) and
code not in (select code from current_table);

sql查询以跨表获取新数据

5 个答案: