FASM IRC Bot Prefix

Question

我一直在努力学习如何从一些旧的来源创建一个汇编程序的IRC机器人。除了前缀问题，我的学习一切都很顺利。

机器人的前缀是：

CommandPrefix equ "^^"

前缀的长度加上：

add eax, 2d

我想将前缀更改为“^”，但我无法弄清楚应该更改“添加eax”以使其工作。或者即使这是最好的方法。任何帮助都将不胜感激。

以下是原始代码的想法：

include "win32ax.inc"

entry Bot

CommandPrefix   equ "^^"


section '.code' code readable executable

Bot:
invoke WSAStartup,0101h,WSAData

cmp eax, 0
jne Exit

invoke socket,AF_INET,SOCK_STREAM,0

cmp eax, -1
je Exit

mov dword [SocketDesc], eax

invoke inet_addr,IRCServer

mov dword [SockAddr_IP], eax

invoke htons,IRCPort

mov word [SockAddr_Port], ax

invoke connect,dword [SocketDesc],SockAddr,16d

cmp eax, 0
jne Exit

call GenerateNickname

invoke lstrcpy,SendBuffer,"NICK "

invoke lstrcat,SendBuffer,Nickname

call SendLine

invoke lstrcpy,SendBuffer,"USER "

invoke lstrcat,SendBuffer,Nickname

invoke lstrcat,SendBuffer," 8 * :"

invoke lstrcat,SendBuffer,Nickname

call SendLine

GetMotd:
call RecvLine
call HandlePing

mov ecx, 0

IsMotd:
cmp dword [ReturnBuffer + ecx], "MOTD"
je HaveMotd

cmp byte [ReturnBuffer + ecx], 0d
je GetMotd

inc ecx
jmp IsMotd

HaveMotd:
invoke lstrcpy,SendBuffer,"JOIN "

invoke lstrcat,SendBuffer,Channel

invoke lstrcat,SendBuffer," "

call SendLine

RecvCommand:
call RecvLine
call HandlePing

mov ecx, 0

IsCommand:
cmp word [ReturnBuffer + ecx], CommandPrefix
je HaveCommand

cmp byte [ReturnBuffer + ecx], 0
je RecvCommand

inc ecx
jmp IsCommand

HaveCommand:
mov ebx, ReturnBuffer
add ebx, ecx
add ebx, 2d                       ;add length of command prefix

invoke lstrcpy,CommandBuffer,ebx

call ExecuteCommand

jmp RecvCommand