Question

我一直收到错误，表示无法找到表格中的列。无法弄清楚为什么会这样。列名称似乎拼写正确。

我收到此错误： 06-11 21:27:02.701 3703-3703/com.example.luca.contatti E/SQLiteLog﹕ (1) table Contatti has no column named imageUri

这是我的DatabaseHandler页面：

public class DatabaseHandler extends SQLiteOpenHelper {
    public static final String DB_NAME = "dbContatti",
        TABLE = "Contatti",
        ID = "id",
        NAME = "name",
        PHONE = "phone",
        EMAIL = "email",
        ADDRESS = "address",
        IMAGEURI = "imageUri";
public static final int DB_VERSION = 4;

public DatabaseHandler(Context context) {
    super(context, DB_NAME, null, DB_VERSION);
}


@Override
public void onCreate(SQLiteDatabase db) {
    //Creazione della tabella per il DB
    db.execSQL("CREATE TABLE " + TABLE + "(" + ID + " INTEGER PRIMARY KEY AUTOINCREMENT," + NAME + "TEXT," + PHONE + "TEXT," + EMAIL + "TEXT," + ADDRESS + "TEXT," + IMAGEURI + "TEXT " + ")");

}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    db.execSQL("DROP TABLE IF EXISTS " + TABLE);

    onCreate(db);
}

// CRUD: CREATE

public void createContact (ContactList contact){
    SQLiteDatabase db = getWritableDatabase();

    ContentValues values = new ContentValues();

    values.put(NAME, contact.getName());
    values.put(PHONE, contact.getPhone());
    values.put(EMAIL, contact.getEmail());
    values.put(ADDRESS, contact.getAddress());
    values.put(IMAGEURI, contact.getImageUri().toString());

    db.insert(TABLE, null, values);
    db.close();
}

//CRUD: READ

public ContactList getContact(int id){
    SQLiteDatabase db = getReadableDatabase();

    Cursor cursor = db.query(TABLE, new String[] {ID, NAME, PHONE, EMAIL, ADDRESS, /*IMAGEURI*/}, ID + "=?", new String[] {String.valueOf(id)},null,null,null,null );

    if (cursor != null)
        cursor.moveToFirst();

    ContactList contact = new ContactList(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), Uri.parse(cursor.getString(5)));
    db.close();
    cursor.close();
    return contact;
}

//CRUD: UPDATE

public int updateContact(ContactList contact){
    SQLiteDatabase db = getWritableDatabase();

    ContentValues values = new ContentValues();

    values.put(NAME, contact.getName());
    values.put(PHONE, contact.getPhone());
    values.put(EMAIL, contact.getEmail());
    values.put(ADDRESS, contact.getAddress());
    values.put(IMAGEURI, contact.getImageUri().toString());

    return db.update(TABLE, values, ID + "=?", new String[] { String.valueOf(contact.getId()) });
}

//CRUD: DELETE

public void deleteContact(ContactList contact){
    SQLiteDatabase db = getWritableDatabase();

    db.delete(TABLE, ID + "=?", new String[] {String.valueOf(contact.getId())});
    db.close();
}

public int getContactsCount(){
    SQLiteDatabase db = getReadableDatabase();

    Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE, null);
    int count = cursor.getCount();
    db.close();
    cursor.close();
    return count;
}

public List<ContactList> getAllContacts(){
    List<ContactList> contacts = new ArrayList<ContactList>();

    SQLiteDatabase db = getWritableDatabase();
    Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE, null);

    if(cursor.moveToFirst()){
        do {
            ContactList contact = new ContactList(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), Uri.parse(cursor.getString(5)));
            contacts.add(contact);
        }
        while (cursor.moveToNext());
    }
    return contacts;
}
}

此外，当我删除此声明时：

values.put(IMAGEURI, contact.getImageUri().toString());

我对其他陈述有疑问。

我可以做些什么来解决这个问题？请帮帮我!!

Answer 1

首先，您必须在每个列名称及其类型之间放置空格：

db.execSQL("CREATE TABLE " + TABLE + "(" + ID + " INTEGER PRIMARY KEY AUTOINCREMENT," + NAME + " TEXT," + PHONE + " TEXT," + EMAIL + " TEXT," + ADDRESS + " TEXT," + IMAGEURI + " TEXT " + ")");

其次，在你的光标中：

Cursor cursor = db.query(TABLE, new String[] {ID, NAME, PHONE, EMAIL, ADDRESS, /*IMAGEURI*/}, ID + "=?", new String[] {String.valueOf(id)},null,null,null,null );

你写了/*IMAGEURI*/！因此，某些行以后，cursor.getString(5)不存在，并且崩溃也是正常的：

ContactList contact = new ContactList(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), Uri.parse(cursor.getString(5)));

最后确保您的Datamodel已更新。如果您刚刚在先前的调试会话期间创建了数据库时添加了imageUri列，则它将崩溃。你很好地覆盖了onUpgrade方法来删除现有的表，但我希望你也不会忘记增加数据库版本值; - ）

Android SQLite问题：'表[...]没有名为'错误的列

1 个答案: