我的发票清单如下
def invoices = [
'LEDES98BI V2',
'LINE|INVOICE_DATE|INVOICE_NUMBER|INVOICE_TOTAL',
'1|20150301|INV-Error_Test1|22',
'2|20150301|INV-Error_Test1|24',
'3|20150301|INV-Error_Test2|26',
'4|20150301|INV-Error_Test2|28,']
我正在尝试使用INVOICE_NUMBER
对上述集合进行groupBy并尝试使用INVOICE_NUMBER
和行作为值来实现地图,代码下面是
def lines = invoices*.split('\\|').findAll{ it.size()>1 }
def heads = lines.first()
def invoiceMap = lines.tail().collect{ [heads, it].transpose().collectEntries() }.groupBy{ it.INVOICE_NUMBER }
如果我打印invoiceMap
我得到了我想要的地图
[INV-Error_Test1:[[LINE:1, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test1, INVOICE_TOTAL:22],
[LINE:2, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test1, INVOICE_TOTAL:24]],
INV-Error_Test2:[[LINE:3, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test2, INVOICE_TOTAL:26],
[LINE:4, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test2, INVOICE_TOTAL:28,]]
]
但是如果INVOICE_NUMBER
在invoices
地图中有任何空格,我的代码就不起作用了。有人可以帮助我使用INVOICE_NUMBER
上的空白区域来处理我的代码吗?
答案 0 :(得分:2)
使用正确的CSV解析器,而不是自己动手。
@Grab('com.xlson.groovycsv:groovycsv:1.0')
import static com.xlson.groovycsv.CsvParser.parseCsv
def invoices = [
'LEDES98BI V2',
'LINE|INVOICE_DATE|INVOICE_NUMBER|INVOICE_TOTAL',
'1|20150301|INV-Error_Test1|22',
'2|20150301|INV-Error_Test1|24',
'3|20150301|INV-Error_Test2|26',
'4|20150301|INV-Error_Test2|28,']
def data = parseCsv(invoices.drop(1).join('\n'), separator:'|')
def invoiceMap = data.collect().groupBy { it.INVOICE_NUMBER }
或列标题中有空格:
def invoices = [
'LEDES98BI V2',
'LINE|INVOICE_DATE|INVOICE NUMBER|INVOICE_TOTAL',
'1|20150301|INV-Error_Test1|22',
'2|20150301|INV-Error_Test1|24',
'3|20150301|INV-Error_Test2|26',
'4|20150301|INV-Error_Test2|28,']
def data = parseCsv(invoices.drop(1).join('\n'), separator:'|')
def invoiceMap = data.collect().groupBy { it.'INVOICE NUMBER' }
答案 1 :(得分:0)
你只需要引用你的名字,就像这样
with open('CSVFile1.csv', 'rb') as csvfile:
fh = csv.reader(csvfile)
wfh = open('CSVFile2.csv', 'ab')
for row in fh:
if user_input in row[3] and int(integer_input) > 5:
row.append(integer_input)
writer = csv.writer(wfh)
writer.writerow(row)
wfh.close()