Question

var student = [{
    "fname": "Jackie",
    "mname": "Lee",
    "lname": "Li"
}, {
    "fname": "Ken",
    "mname": "Ryu",
    "lname": "Sha"
}];

for (var i = 0; i < student.length; i++) {
    console.log(student[i].fname + " " + student[i].mname + ". " + student[i].lname ? student[i].fname + " " + student[i].mname + ". " + student[i].lname + " , " : " ");
}

我正在尝试将a td中的名称组合起来，这些名称来自数组。我能够通过上面的代码组合名称。问题是在姓氏上还有一个,只想在没有更多名字的情况下摆脱逗号。我被这个简单的逗号打了几个小时。任何想法都是适用的。

FIDDLE

Answer 1

一种简单的方法是构建一个数组，然后使用.join(", ")：

＆＃13;

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}];

var names = [];
for (var i = 0; i < student.length; i++) {
  names.push(student[i].fname + " " + student[i].mname + ". " + student[i].lname);
}
snippet.log(names.join(", "));

＆＃13;

<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

＆＃13;

Array#map：

甚至可以更简洁

＆＃13;

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}];

snippet.log(student.map(function(entry) {
  return entry.fname + " " + entry.mname + ". " + entry.lname;
}).join(", "));

＆＃13;

<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

＆＃13;

Answer 2

如果我理解你的问题，那么应该这样做：

for(var i = 0 ; i < student.length; i++){
  var name = student[i].fname + " " + student[i].mname + ". " + student[i].lname ?  student[i].fname + " " + student[i].mname + ". " + student[i].lname: " ";
  if (i < (student.length - 1)) {
      name += ',';
  }
}

Answer 3

试试这段代码

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}]

for (var i = 0; i < student.length; i++) {
  var out = student[i].fname + " " + student[i].mname + ". " + student[i].lname;
  if (i < student.length - 1) {
    out += ", ";
  } else {
    out += " ";
  }
  snippet.log(out);
}

<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

Answer 4

试试这个jsfiddle

你应该这样使用：

var student = [{
     "fname": "Jackie",
         "mname": "Lee",
         "lname": "Li"
 }, {
     "fname": "Ken",
         "mname": "Ryu",
         "lname": "Sha"
 }]

 for (var i = 0; i < student.length; i++) {
     console.log(student[i].fname + " " + student[i].mname + ". " + student[i].lname + ((i < student.length - 1) ? ", " : " "));
 }

组合数据/变量jquery

4 个答案: