Question

我从oracle docs学习java。

我现在正在学习BufferedInputStream available();方法

我拿了示例代码并编写了以下代码

import java.io.BufferedInputStream;
import java.io.FileInputStream;
import java.io.InputStream;

public class BufferInput {
   public static void main(String[] args) throws Exception {

      InputStream inStream = null;
      BufferedInputStream bis = null;

      try{
         // open input stream test.txt for reading purpose.
         inStream = new FileInputStream("c:/test.txt");

         // input stream is converted to buffered input stream
         bis = new BufferedInputStream(inStream);      

         // read until a single byte is available
         while( bis.available() > 0 )
         {
            // get the number of bytes available
            Integer nBytes = bis.available();
            System.out.println("Available bytes = " + nBytes );

            // read next available character
            char ch =  (char)bis.read();

            // print the read character.
            System.out.println("The character read = " + ch );
         }
      }catch(Exception e){
         e.printStackTrace();
      }finally{

         // releases any system resources associated with the stream
         if(inStream!=null)
            inStream.close();
         if(bis!=null)
            bis.close();
      }
   }
}

当我运行此代码时，

显示以下输出：

Available bytes = 2
The character read = V
Available bytes = 1
The character read = A

但在我的test.txt文件中，内容是SELVA。

任何人都可以帮我解决这个问题吗？

Answer 1

我在我的日食中使用了你的代码，输出似乎很好：

Available bytes = 5
The character read = s
Available bytes = 4
The character read = e
Available bytes = 3
The character read = l
Available bytes = 2
The character read = v
Available bytes = 1
The character read = a

BufferedInputStream的available（）表现不尽如人意

1 个答案: