Question

我在两个变量中有两个值，即字符串

$var1 = "A$2800";
$var2 = "A$1500";

我想要计算

$diff = $var1 - $var2;

应该{{1}}计算1300和2800的差异

Answer 1

您可以使用explode()

$var1 = explode("$", $var1); //$var1 is now an array containing: [0]=A, [1]=2800
$var2 = explode("$", $var2); //$var2 is now an array containing: [0]=A, [1]=1500

$diff = $var1[1] - $var2[1]; //$diff contains 1300

Answer 2

如果字符串中的前缀始终为2个字符，请开始使用substr：

$val1 = substr("A$3000" , 2 , -2);

Answer 3

您不能简单地将其添加到数字，首先您需要删除A$。例如。使用substr。

$var1 = "A$2800";
$var2 = "A$1500";

$num1 = (int)substr($var1, 2);
$num2 = (int)substr($var2, 2);

$diff = $num1 - $num2;

Answer 4

您可以删除A$，然后计算 -

$var1 = "A$2800";
$var2 = "A$1500";
$var1 = str_replace("A$", '', $var1); //2800
$var2 = str_replace("A$", '', $var2); //1500

$diff = $var1 - $var2; //1300

Answer 5

preg_replace('/\D/', '', $c)

以上内容应删除所有字符，仅保留数字。

$var1 = preg_replace('/\D/', '', "A$2800");
$var2 = preg_replace('/\D/', '', "A$1500");
$diff = $var1 - $var2;
echo $diff;

对于变量，只需修改第三个参数并插入变量即可。例如：

$var1 = preg_replace('/\D/', '', $var1);

：）

PHP将字符串转换为int并计算

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