Question

我是这里的新手，我正在尝试让python识别另一个内部的.split（）列表。这有点难以解释，所以我会表明：

>>>   #this is a function that separates the last word in the string, spliting the string by words and then transforming it into a list and the using the len() to know what is the position of the last item in the list, so that I can return it to another var.

>>> def lastWord(phrase):
       phrase = list(phrase.split()[len(list(phrase.split()))-1:]))
       return phrase

>>> x = "Hello World"
>>> d = lastWord(x)
>>> d
['World']
>>> x.split()
['Hello', 'World']
>>> one_list ["Hello", "World", "Anything"]
>>> one_list
['Hello', 'World', 'Anything']
>>> x.split() in one_list
False
>>> list(x.split()) in one_list
False
>>> d in one_list
False

如何让它识别使用.split（）在另一个列表中创建的生成的拆分列表？

Answer 1

问题是因为你试图在[＆＃34; Hello＆＃34;，＆＃34; World＆＃34;，＆＃]中找到[＆＃39; Hello＆＃39;，＆＃39; World＆＃39;] ＃34;任何＆＃34;]

时会给你真实的

one_list = [["Hello", "World"], "Anything"]

Answer 2

更改以下内容 -

x.split() in one_list

到 -

exists = True
for item in x.split():
    if item not in one_list:
        exists = False
        break
print exists

Answer 3

你不能在＆＃34;中使用＆＃34;像那样测试每个单独的项目：

x.split() in one_list

试试这个：

all(x in one_list for x in x.split())

函数返回列表显示False python

3 个答案: