Question

我遇到SQLiteAssetHelper（https://github.com/jgilfelt/android-sqlite-asset-helper）的问题：我无法正确打开数据库中的表格。

数据库是使用sqlitebrowser制作的我有一个数据库，其中两个表填充了我想用Cursor访问的字符串，但是当我尝试访问它们时，它给了我一个错误：

android.database.sqlite.SQLiteException: no such table: Verbs (code 1): , while compiling: SELECT LatinVerbs FROM Verbs WHERE _rowid_=?

我的数据库合同：

import android.provider.BaseColumns;

public class DatabaseContract {
    public static final int DATABASE_VERSION = 1; 
    public static final String DATABASE_NAME = "verbtable.db";
    private static final String TEXT_TYPE = " TEXT";
    private static final String COMMA_SEP = ",";

    private DatabaseContract(){}
    public static abstract class Table1 implements BaseColumns{
        public static final String TABLE_NAME = "Verbs";
        public static final String COLUMN_NAME_TITLE_COL1 = "LatinVerbs";
        public static final String COLUMN_NAME_TITLE_COL2 = "Translation";
        public static final String SQL_CREATE_ENTRIES =
                "CREATE TABLE " + TABLE_NAME + " (" +
                        _ID + " INTEGER PRIMARY KEY," +
                        COLUMN_NAME_TITLE_COL1 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL2 + TEXT_TYPE + COMMA_SEP +
                        " )";
        public static final String SQL_DELETE_ENTRIES = "DROP TABLE IF EXISTS " + TABLE_NAME;

    }
    public static abstract class Table2 implements BaseColumns{
        public static final String TABLE_NAME = "Structure";
        public static final String COLUMN_NAME_TITLE_COL1 = "infinitive";
        public static final String COLUMN_NAME_TITLE_COL2 = "pers_id";
        public static final String COLUMN_NAME_TITLE_COL3 = "ind_praes_act";
        public static final String COLUMN_NAME_TITLE_COL4 = "ind_praes_pass";
        public static final String COLUMN_NAME_TITLE_COL5 = "ind_impf_act";
        public static final String COLUMN_NAME_TITLE_COL6 = "ind_impf_pass";
        public static final String COLUMN_NAME_TITLE_COL7 = "ind_fut_act";
        public static final String COLUMN_NAME_TITLE_COL8 = "ind_fut_pass";
        public static final String SQL_CREATE_ENTRIES =
                "CREATE TABLE " + TABLE_NAME + " (" +
                        _ID + " INTEGER PRIMARY KEY," +
                        COLUMN_NAME_TITLE_COL1 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL2 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL3 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL4 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL5 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL6 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL7 + TEXT_TYPE + COMMA_SEP +
                        COLUMN_NAME_TITLE_COL8 + TEXT_TYPE + COMMA_SEP +
                        " )";
        public static final String SQL_DELETE_ENTRIES = "DROP TABLE IF EXISTS " + TABLE_NAME;
    }
}

我的游标：

Cursor c = db.query(DatabaseContract.Table1.TABLE_NAME, columns, "_rowid_=?", selectionArgsRoot, null, null, null);

int index = c.getColumnIndexOrThrow(columns[0]);
c.moveToFirst();
do {
    rootResult = c.getString(index);
 } while (c.moveToNext());

c.close();

c = db.query(DatabaseContract.Table2.TABLE_NAME, columnSuffix, "pers_id=?", selectionArgsSuffix, null, null, null);
index = c.getColumnIndexOrThrow(columnSuffix[0]);
c.moveToFirst();
do{
    suffix = c.getString(index);
}while(c.moveToNext());
c.close();

我尝试更新数据库版本并重新启动我运行代码的模拟器，但错误仍然存在。

Answer 1

您以前是否曾使用数据库创建程序运行该程序？如果有，则需要增加数据库版本号。这需要在添加时完成。

您还可以尝试在模拟器中卸载应用并重新运行全新安装。

Answer 2

两个表都没有创建 事实上，您在每个表格的最后一列之后添加了额外逗号。

下面：

COLUMN_NAME_TITLE_COL2 + TEXT_TYPE + COMMA_SEP +
" )";

在这里：

COLUMN_NAME_TITLE_COL8 + TEXT_TYPE + COMMA_SEP +
" )";

这些行实际上应该是：

COLUMN_NAME_TITLE_COL2 + TEXT_TYPE + ")";

和

COLUMN_NAME_TITLE_COL8 + TEXT_TYPE + ")";

分别

无法访问单个数据库上的两个表

2 个答案: