Question

我是法国人，对我的英语很抱歉，我需要一些帮助，我正在尝试从我的文本文件中获得一个数组（或ArrayList），如下所示：

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,2,2,2,2,2,2,2,2,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
2,2,2,2,2,2,2,2,0,0,0,2,2,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,0,2,2
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
2,2,2,2,2,2,2,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0

我已经尝试过了：

ArrayList<ArrayList<Integer>> multi=new ArrayList();
    ArrayList<Integer> line=new ArrayList();
    AssetManager assetManager = getAssets();
    BufferedReader reader = null;
    try {
        reader = new BufferedReader(new InputStreamReader(assetManager.open("level/world1/w1-1.txt"), "UTF-8"));
        String mLine = reader.readLine();

        while (mLine != null) {
            mLine = reader.readLine();
        }
    } catch (IOException e) {
    } finally {
        if (reader != null) {
            try {
                reader.close();
            } catch (IOException e) {
            }
        }
    }

但我不知道如何将我的mLine放入我的多阵列中：/

感谢您的帮助！：）

Answer 1

看起来您已经编写了正确读取文件的代码，所以您的问题实际上是关于如何将逗号分隔的String解析为一系列Integer对象并存储它们在List中以有效的方式。

Java已经有了很好的工具来进行简单的文本解析，在这种情况下使用Scanner似乎很合适。

为你的内循环尝试这样的事情：

    while (mLine != null) {
        Scanner sc = new Scanner(mLine);  // create a Scanner for each line
        sc.useDelimiter(",");             // parse the line for tokens delimited by commas

        ArrayList<Integer> inner = new ArrayList<>();
        while (sc.hasNextInt()) {
            inner.add(sc.nextInt());      // add each number found to the inner list
        }
        multi.add(inner);                 // add the inner list to the outer list

        sc.close();

        mLine = reader.readLine();
    }

请注意，Scanner允许您设置要解析的分隔符，并且具有它知道的几个内置类型，因此您不需要进行任何中间String创建或者输入。

Answer 2

尝试：

List<List<Integer>> matrix = new ArrayList();

BufferedReader reader = null;
try {
    reader = new BufferedReader(...);
    String line = null;
    while( ( line = reader.readLine() ) != null ) {
        String[] tokens = line.split(",");
        List<Integer> row = new ArrayList();
        for (int i = 0; i < tokens.length; i++) {
            row.add(Integer.parseInt(tokens[i]));
        }
        matrix.add(row);
    }
} finally {
    if (reader != null) {
        reader.close();
    }
}

我建议在文件的第一行包含文件和列的数量。类似的东西：

30,25
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
(...)

然后你可以读它并相应地创建一个int [] []多数组（从而提高内存使用率）。

从文本android java获取数组

2 个答案: