我正在尝试将Python 2.7代码转换为Python 3代码,并且我从urllib请求模块收到类型错误。
我使用内置的2to3 Python工具转换以下工作的urllib和urllib2 Python 2.7代码:
import urllib2
import urllib
url = "https://www.customdomain.com"
d = dict(parameter1="value1", parameter2="value2")
req = urllib2.Request(url, data=urllib.urlencode(d))
f = urllib2.urlopen(req)
resp = f.read()
2to3模块的输出是以下Python 3代码:
import urllib.request, urllib.error, urllib.parse
url = "https://www.customdomain.com"
d = dict(parameter1="value1", parameter2="value2")
req = urllib.request.Request(url, data=urllib.parse.urlencode(d))
f = urllib.request.urlopen(req)
resp = f.read()
运行Python 3代码时会产生以下错误:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-56-206954140899> in <module>()
5
6 req = urllib.request.Request(url, data=urllib.parse.urlencode(d))
----> 7 f = urllib.request.urlopen(req)
8 resp = f.read()
C:\Users\Admin\Anaconda3\lib\urllib\request.py in urlopen(url, data, timeout, cafile, capath, cadefault, context)
159 else:
160 opener = _opener
--> 161 return opener.open(url, data, timeout)
162
163 def install_opener(opener):
C:\Users\Admin\Anaconda3\lib\urllib\request.py in open(self, fullurl, data, timeout)
459 for processor in self.process_request.get(protocol, []):
460 meth = getattr(processor, meth_name)
--> 461 req = meth(req)
462
463 response = self._open(req, data)
C:\Users\Admin\Anaconda3\lib\urllib\request.py in do_request_(self, request)
1110 msg = "POST data should be bytes or an iterable of bytes. " \
1111 "It cannot be of type str."
-> 1112 raise TypeError(msg)
1113 if not request.has_header('Content-type'):
1114 request.add_unredirected_header(
TypeError: POST data should be bytes or an iterable of bytes. It cannot be of type str.
我还阅读了另外两张提及日期编码的门票(ticket1和ticket2)。
当我将行f = urllib.request.urlopen(req)
更改为f = urllib.request.urlopen(req.encode('utf-8'))
时,我收到以下错误:AttributeError: 'Request' object has no attribute 'encode'
我对如何使Python 3代码工作感到困惑。你能帮我吗?
答案 0 :(得分:34)
从docs 注意,urlencode的params输出在作为数据发送到urlopen之前被编码为字节:
expr
答案 1 :(得分:3)
试试这个:
url = 'https://www.customdomain.com'
d = dict(parameter1="value1", parameter2="value2")
f = urllib.parse.urlencode(d)
f = f.encode('utf-8')
req = urllib.request.Request(url, f)
你的问题在于你处理字典的方式。
答案 2 :(得分:0)
我在ZOHO CRM API V2中使用了python请求模块。它的工作没有任何问题。 这是带有GET请求的示例工作代码:
import json
import requests
# API methods - https://www.zoho.com/crm/developer/docs/api/api-methods.html
# getrecords API Call
module_name = 'Deals'
authtoken = '*****'
api_url = "https://crm.zoho.com/crm/private/json/"+module_name+"/getRecords?authtoken="+authtoken+"&scope=crmapi&fromIndex=1&toIndex=2"
# GET Request
request_response = requests.get(
url=api_url
)
print(json.dumps(json.loads(request_response.text), sort_keys=True, indent=4, separators=(",", ": ")))
json_response = json.loads(request_response.text)