此脚本无法按预期工作:
#!/usr/bin/expect
set timeout 2
set server [lindex $argv 0]
set user [lindex $argv 1]
set password [lindex $argv 2]
set mac [lindex $argv 3]
set interface "po1"
spawn ssh $user@$server
expect "Password:"
send -- "$password\n"
expect "*>"
send "show mac address-table address $mac\n"
# 100 1cc1.de65.441c dynamic ip,ipx,assigned,other Port-channel43
expect -re { (\d+) *($mac) *(dynamic|static) *(.*) *(.*)} {
set interface $expect_out(5,string)
expect "*>"
send "show interface $interface status\n"
}
send "exit\n"
interact
在上面发出show mac命令后,输出包含一行,看起来就像下面评论的一行。但是下面的期望-re块永远不会被命中,使它超时并发送退出命令。
示例输出: spawn ssh user @ host 密码:
================= Host login banner =================
host>show mac address-table address 1cc1.de65.441c
Unicast Entries
vlan mac address type protocols port
---------+---------------+--------+---------------------+-------------------------
100 1cc1.de65.441c dynamic ip,ipx,assigned,other Port-channel43
host>exit
Connection to host closed.
答案 0 :(得分:1)
您的正则表达式不正确,并且不会发生内部替换。即$mac
不会被替换,因为它在括号内。
expect {
-re "\\d+\\s+$mac\\s+(dynamic|static)\\s+\\S+\\s+(\\S+)" { set interface $expect_out(2,string); # Add your further code}
}