Question

您好我已经开始使用Laravel 5并发现它非常有用。现在我在Auth部分。我想要做的是相当于laravel中的这段代码：

if($_SESSION['user'] == $_GET['user'])
{
 // I can only see this page
}

这就是我的控制器中的功能：

public function viewProfile(User $user)
{
    $cur_user = \Auth::user()->username;
    return view('profile', compact('user', 'cur_user'));
}

例如，网址就像这个http://localhost:8000/profile/sorxrob。 sorxrob有用户名。我怎样才能Auth::user() ==在laravel中获取网址？

Answer 1

if(Auth::user()->id == $user->id)
{
    $cur_user = \Auth::user()->username;
    return view('profile', compact('user', 'cur_user'));
}

Answer 2

有Middleware。

创建中间件：

php artisan make:middleware OwnerMiddleware

namespace App\Http\Middleware;

use App\Article;
use Closure;
use Illuminate\Contracts\Auth\Guard;

class OwnerMiddleware
{
    /**
     * The Guard implementation.
     *
     * @var Guard
     */
    protected $auth;

    /**
     * Create a new filter instance.
     *
     * @param  Guard  $auth
     * @return void
     */
    public function __construct(Guard $auth)
    {
        $this->auth = $auth;
    }

    /**
     * Handle an incoming request.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Closure  $next
     * @return mixed
     */
    public function handle($request, Closure $next)
    {
        $currentUser = $this->auth->getUser();

        if (/* here goes your condition to check user*/) {
            abort(403, 'Unauthorized action.');
        }

        return $next($request);
    }
}

将其添加到app\Http\Kernel.php：

protected $routeMiddleware = [
    'owner' => 'App\Http\Middleware\OwnerMiddleware',
];

在路线中使用中间件：

Route::group(['middleware' => ['owner']], function() {
    // your route
});

Laravel Auth检查url是否等于User Logged In

2 个答案: