我是codeigniter的新手,版本是2.1.4,我在sql方法的导出数据库中有问题。我在下面给出了代码,当我运行代码时,它不会显示任何错误。当我检查给定的路径时,没有创建文件。谁能帮我。提前谢谢。
function backup_tables($host='localhost',$user='arts',$pass='arts123',$name='arts',$tables = 'sales')
{
$link = mysql_connect($host,$user,$pass);
mysql_select_db($name,$link);
//get all of the tables
if($tables == '*')
{
$tables = array();
$result = mysql_query('SHOW TABLES');
while($row = mysql_fetch_row($result))
{
$tables[] = $row[0];
}
}
else
{
$tables = is_array($tables) ? $tables : explode(',',$tables);
}
$return = "";
//cycle through
foreach($tables as $table)
{
$result = mysql_query('SELECT * FROM '.$table);
$num_fields = mysql_num_fields($result);
//$return.= 'CREATE TABLE '.$table.';';
$row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table));
$return.= "\n\n".$row2[1].";\n\n";
for ($i = 0; $i < $num_fields; $i++)
{
while($row = mysql_fetch_row($result))
{
$return.= 'INSERT INTO '.$table.' VALUES(';
for($j=0; $j<$num_fields; $j++)
{
$row[$j] = addslashes($row[$j]);
// $row[$j] = ereg_replace("\n","\\n",$row[$j]);
$row[$j] = preg_replace("#\n#", "\\n", $row[$j]);
if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; }
if ($j<($num_fields-1)) { $return.= ','; }
}
$return.= ");\n";
}
}
$return.="\n\n\n";
}
$backup_file = '/var/www/html/art/assets/uploads/csv/backup-'.date('M').'-'.date('Y').'.sql';
//save file
$handle = fopen($backup_file,'w+');
fwrite($handle,$return);
fclose($handle);
exit;
}