Question

我想通过链接替换单词组。

单词组在多维数组中定义。将有数以千计的术语被替换，因此需要一个无索引的，轻量级和多维的阵列。

当术语后面括号或方括号内时，不应该替换任何内容。

问题：正则表达式本身工作正常，但当单词组包含像+这样的正则表达式语法字符时，替换会中断？ /（等所以我需要掩盖它们。我尝试了所有我能想到的变化，但它并不适用于所有情况。我不能用$ text或$ s掩盖它们。

<?php

$text = "<html><body><pre>
Replace all foo / bar / baz cases here:
Case 1: Text Foo text.
Case 2: Text 'Foo' Bar text Foo.
Case 3: Text Foobar (2) text.
Case 4: Text Bar & Baz.
Case 5: Text Bar Baz?
Case 6: Text Bar? & Baz?
Case 7: Text Bar-X.

Replace nothing here (text followed by brackets) or [inside square brackets]: 
Case 1: Text Foo (text).
Case 2: Text 'Foo' Bar (text) Foo (text).
Case 3: Text Foobar (2) (text).
Case 4: Text Bar & Baz (text).
Case 5: Text Bar Baz (text).
Case 6: Text Bar? & Baz (text).
Case 7: Text Bar-X (text).
Case 8: [Text Foo]
</pre></body></html>";

$s = array(
  array("t" => "Foo",         "u" => "http://www.foo.net"),
  array("t" => "'Foo' Bar",   "u" => "http://www.foo.net"),
  array("t" => "Foobar (2)",  "u" => "http://www.foo.net"),
  array("t" => "Bar & Baz",   "u" => "http://www.foo.net"),
  array("t" => "Bar Baz?",    "u" => "http://www.foo.net"),
  array("t" => "Bar? & Baz?", "u" => "http://www.foo.net"),
  array("t" => "Bar-X",       "u" => "http://www.foo.net")
 );

$replaced = $text;
foreach ($s as $i => $row) {
# $replaced = preg_replace('/(?='.preg_quote($row["t"]).'[^\]][^(]+$)\b'.preg_quote($row["t"]).'\b/mS',
# $replaced = preg_replace('/(?='.preg_quote($row["t"], '/').'[^\]][^(]+$)\b'.preg_quote($row["t"], '/').'\b/mS',
# $replaced = preg_replace('/(?=\Q'.$row["t"].'\E[^\]][^(]+$)\b\Q'.$row["t"].'\E\b/mS',
    $replaced = preg_replace('/(?='.$row["t"].'[^\]][^(])\b'.$row["t"].'\b/mS',
                           '<a href="'.$row["u"].'">'.$row["t"].'</a>',
                           $replaced);
 }
echo $replaced;

?>

Answer 1

这至少应该在提供的测试用例中起作用：

$replaced = preg_replace('/([.,\s!^]+)('.preg_quote($row["t"],'/').')([.,\s!$]+)(?!\()/mS',
                           '$1<a href="'.$row["u"].'">$2</a>$3',
                           $replaced);

当您的匹配本身包含在某些边界内时（例如\b），

Foobar (2)无法按预期工作，因此您应该专门提供允许的字符列表。我很快将[.,\s!^]和[.,\s!$]放在那里，您可能需要根据您的规格添加一些允许的字符（例如-，_？）

Answer 2

我不完全确定你要做什么，但我看到“单词组包含正则表达式语法字符时中断”这让我觉得你需要做的就是逃避这些字符......即在它们之前放一个\

修改

我也很喜欢这个，但是如果能告诉你我有什么，也许它可以帮到你：

<?php $text = "<html><body><pre> Replace all foo / bar / baz cases here: Case 1: Text Foo text. Case 2: Text 'Foo' Bar text Foo. Case 3: Text Foobar (2) text. Case 4: Text Bar & Baz. Case 5: Text Bar Baz? Case 6: Text Bar? & Baz? Case 7: Text Bar-X. Replace nothing here (text followed by brackets) or [inside square brackets]: Case 1: Text Foo (text). Case 2: Text 'Foo' Bar (text) Foo (text). Case 3: Text Foobar (2) (text). Case 4: Text Bar & Baz (text). Case 5: Text Bar Baz (text). Case 6: Text Bar? & Baz (text). Case 7: Text Bar-X (text). Case 8: [Text Foo] </pre></body></html>"; function convertRegexChars($string) { $converted = str_replace("?","?",$string); $converted = str_replace(".",".",$converted); $converted = str_replace("*","*",$converted); $converted = str_replace("+","+",$converted); return $converted; } $s = array( array("t" => "Foo", "u" => "http://www.foo.net"), array("t" => "'Foo' Bar", "u" => "http://www.foo.net"), array("t" => "Foobar (2)", "u" => "http://www.foo.net"), array("t" => "Bar & Baz", "u" => "http://www.foo.net"), array("t" => "Bar Baz?", "u" => "http://www.foo.net"), array("t" => "Bar? & Baz?", "u" => "http://www.foo.net"), array("t" => "Bar-X", "u" => "http://www.foo.net") ); $replaced = convertRegexChars($text); foreach ($s as $i => $row) { $txt = convertRegexChars($row['t']); $replaced = preg_replace('/(?='.$txt.'[^\]][^(])\b'.$txt.'\b/mS', '<a href="'.$row["u"].'">'.$txt.'</a>', $replaced); } echo $replaced; ?>

preg_replace数组：掩码正则表达式字符问题

2 个答案: