我对XSLT比较陌生,我正在开发一个涉及xml和xslt1.0的项目。
我有一个看起来像
的xml代码(简化版)<visualChildren>
<object class="com.zerog.ia.installer.InstallSet" >
<installChildren>
<object class="com.zerog.ia.installer.InstallBundle" objectID="33110emc908m">
<property></property>
</object>
<object class="com.zerog.ia.installer.InstallBundle" objectID="43110emc9667m">
<property></property>
</object>
</installChildren>
</object>
</visualChildren>
我需要迭代地收集所有对象ID并存储为
<object RefId={ObjectId} />
在visualChildren下。预期结果是
<visualChildren>
<object class="com.zerog.ia.installer.InstallSet" >
<installChildren>
<object class="com.zerog.ia.installer.InstallBundle" objectID="33110emc908m">
<property></property>
</object>
<object class="com.zerog.ia.installer.InstallBundle" objectID="43110emc9667m">
<property></property>
</object>
</installChildren>
</object>
<object RefId=33110emc908m />
<object RefId=43110emc9667m />
</visualChildren>
任何人都可以帮助我用xslt 1.0来实现这个目标
答案 0 :(得分:1)
您可以修改身份转换以完全复制除visualChildren/object
元素之外的所有内容,这些元素可以按原样复制并加上您请求的RefId
属性:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="visualChildren/object">
<xsl:copy>
<xsl:attribute name="RefId">
<xsl:for-each select="//@objectID">
<xsl:value-of select="."/>
<xsl:if test="position() != last()">
<xsl:text> </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
将上述XSLT应用于您的输入XML:
<visualChildren>
<object class="com.zerog.ia.installer.InstallSet" >
<installChildren>
<object class="com.zerog.ia.installer.InstallBundle" objectID="33110emc908m">
<property></property>
</object>
<object class="com.zerog.ia.installer.InstallBundle" objectID="43110emc9667m">
<property></property>
</object>
</installChildren>
</object>
</visualChildren>
产生以下输出XML:
<?xml version="1.0" encoding="UTF-8"?>
<visualChildren>
<object RefId="33110emc908m 43110emc9667m"
class="com.zerog.ia.installer.InstallSet">
<installChildren>
<object class="com.zerog.ia.installer.InstallBundle" objectID="33110emc908m">
<property/>
</object>
<object class="com.zerog.ia.installer.InstallBundle" objectID="43110emc9667m">
<property/>
</object>
</installChildren>
</object>
</visualChildren>
根据要求。
注意:您是否希望所有@objectID
属性 下面的某个visualChildren/object
元素而不是 all < / em> 整个文档中的@objectID
属性,然后更改
<xsl:for-each select="//@objectID">
到
<xsl:for-each select=".//@objectID">
答案 1 :(得分:0)
以这种方式尝试:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/visualChildren">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
<xsl:for-each select=".//@objectID">
<object RefId="{.}"/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
注意:强>
如果您要收集的对象始终位于installChildren
下,请替换:
<xsl:for-each select=".//@objectID">
效率更高:
<xsl:for-each select="object/installChildren/object/@objectID">