Question

我的查询遇到了逻辑问题。

我有两个表 Table1 和 Table2 ，其中Table1包含：

value 总结
Id 按
Code 持有Table2

Table2由

组成

Code
Des 代码的文字说明

我要做的是，按Table1.Id分组，Table2.Code上的完全加入，但是，对于每个结果组，我想要显示表2中所有由查询。

示例代码：

SELECT
    Table2.Code, Table1.Id, Table2.DES, 
    SUM(Table1.Value) AS SUM_VAL
FROM 
(
    SELECT 'A' AS Code, 1 AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'A' AS Code, 2 AS Id, 20 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 1 AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 1 AS Id, 30 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 2 AS Id, 50 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 1 AS Id, 40 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 2 AS Id, 60 AS Value FROM DUAL UNION
    SELECT 'D' AS Code, 1 AS Id, 20 AS Value FROM DUAL

) Table1
FULL JOIN
(
    SELECT 'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'D' AS Code, 'This is D' AS DES FROM DUAL
) Table2
ON Table1.Code = Table2.Code
GROUP BY
    Table2.Code, Table1.Id, Table2.DES
ORDER BY
    Table2.Code, Table1.Id ASC

结果：

A   1   This is A   10
A   2   This is A   20
B   1   This is B   40
B   2   This is B   50
C   1   This is C   40
C   2   This is C   60
D   1   This is D   20

必填结果：

A   1   This is A   10
A   2   This is A   20
B   1   This is B   40
B   2   This is B   50
C   1   This is C   40
C   2   This is C   60
D   1   This is D   20
D   2   This is D   0    <- This is the target

Answer 1

你以某种方式显示价值对(D,2)，例如。通过制作包含可能值的代码列表并将NULL翻译为0：

  SELECT code.code,
         code.id,
         des.des,
         NVL (SUM (val.value), 0) sum_val
    FROM (SELECT 'A' code, 1 id FROM DUAL
          UNION
          SELECT 'A', 2 FROM DUAL
          UNION
          SELECT 'B', 1 FROM DUAL
          UNION
          SELECT 'B', 2 FROM DUAL
          UNION
          SELECT 'C', 1 FROM DUAL
          UNION
          SELECT 'C', 2 FROM DUAL
          UNION
          SELECT 'D', 1 FROM DUAL
          UNION
          SELECT 'D', 2 FROM DUAL) code
         INNER JOIN (SELECT 'A' code, 'This is A' des FROM DUAL
                     UNION
                     SELECT 'B', 'This is B' FROM DUAL
                     UNION
                     SELECT 'C', 'This is C' FROM DUAL
                     UNION
                     SELECT 'D', 'This is D' FROM DUAL) des
            ON code.code = des.code
         LEFT OUTER JOIN (SELECT 'A' code, 1 id, 10 VALUE FROM DUAL
                          UNION ALL
                          SELECT 'A', 2, 20 FROM DUAL
                          UNION ALL
                          SELECT 'B', 1, 10 FROM DUAL
                          UNION ALL
                          SELECT 'B', 1, 30 FROM DUAL
                          UNION ALL
                          SELECT 'B', 2, 50 FROM DUAL
                          UNION ALL
                          SELECT 'C', 1, 40 FROM DUAL
                          UNION ALL
                          SELECT 'C', 2, 60 FROM DUAL
                          UNION ALL
                          SELECT 'D', 1, 20 FROM DUAL) val
            ON code.code = val.code AND code.id = val.id
GROUP BY code.code, code.id, des.des
ORDER BY code, id

<{>} UNION ALL用于val，因为可能会发生重复。

无需FULL OUTER JOIN。

Answer 2

如果您想要所有ID和值的组合，请使用cross join获取行，并使用left join来引入其余值：

select t2.code, i.value, t2.desc, coalesce(cnt, 0) as cnt
from (select distinct id from table1) i cross join
     table2 t2 left join
     (select id, value, count(*) as cnt
      from table1
      group by id, value
     ) iv
     on iv.id = i.id and iv.code = t2.code

这比手动列出所有组合要简单得多。

Answer 3

SELECT
    Table2.Code, Table2.NAT, Table2.DES, 
    SUM(Table1.Value) AS SUM_VAL
FROM 
(
    SELECT 'A' AS Code, 'QA' AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'A' AS Code, 'NQA' AS Id, 20 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'QA' AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'QA' AS Id, 30 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'NQA' AS Id, 50 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 'QA' AS Id, 40 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 'NQA' AS Id, 60 AS Value FROM DUAL UNION
    SELECT 'D' AS Code, 'QA' AS Id, 20 AS Value FROM DUAL

) Table1
FULL JOIN
(
    SELECT 'QA' NAT,'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'D' AS Code, 'This is D' AS DES FROM DUAL
    UNION
    SELECT 'NQA' NAT,'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'D' AS Code, 'This is D' AS DES FROM DUAL
) Table2
on TABLE2.NAT = TABLE1.ID
      AND Table2.Code= Table1.Code
GROUP BY
    Table2.Code, Table2.NAT, Table2.DES
ORDER BY
    Table2.Code, Table2.NAT ASC

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3 个答案: