我为jqGrid编写了一个代码但是我无法将数据存入我的jqGrid。
$(document).ready(function () {
jQuery("#jqgrid").jqGrid({
url:"/VendorDetailList.ashx",
dataType: "json",
data: "{}",
height: 'auto',
postData: {
Entity: function () {
return 'vendor';
}
},
colNames: ['vendorrep_id','vendor_id','Name', 'Phone Number', 'Job Title', 'Email','Entity'],
colModel: [{
name: 'vendorrep_id',
index: 'vendorrep_id',
key: true,
search:false,
hidden: true,
editable: true,
editrules: { edithidden: false, readonly: true },
search:false
},
{
name: 'vendor_id',
index: 'vendor_id',
key: true,
search:false,
hidden: true,
editable: true,
editrules: { edithidden: false, readonly: true },
search:false
},
{
name: 'name',
index: 'name',
editable: true,
editrules: {required:true}
}, {
name: 'phone',
index: 'phone',
editable: true
}, {
name: 'jobtitle',
index: 'jobtitle',
editable: true
}, {
name: 'email',
index: 'email',
editable: true
},
{
name: 'Entity', hidden: true, editable: true, editrules: { edithidden: false }, formatter: function () {
return 'Vendor';
},
}
],
data: JSON.parse(result),
rowNum: 10,
mtype: 'POST',
loadonce: true,
rowList: [10, 20, 30],
pager: '#pjqgrid',
sortname: 'CompanyName',
multiselect: true,
multipleSearch:true,
autowidth: true,
height: 'auto',
scrollOffset: 0,
shrinkToFit: true,
//toppager: true,
cloneToTop: true,
ignoreCase: true,
viewrecords: true,
gridview: true,
sortorder: 'asc',
caption: "Vendor Rep",
editurl: '/VendorDetailList.ashx'
});
});
HTTP处理程序代码在这里:
public class VendorList : IHttpHandler, IReadOnlySessionState
{
string MethodName = string.Empty;
string CallBackMethodName = string.Empty;
object Parameter = string.Empty;
DbVendor _DbVendor = new DbVendor();
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "application/json";
MethodName = context.Request.Params["oper"];
Parameter = context.Request.Params;
CallBackMethodName = context.Request.Params["callbackmethod"];
switch (MethodName)
{
case null:
context.Response.Write(GetVendor());
break;
case "getbyid":
context.Response.Write(GetById());
break;
case "add":
context.Response.Write(Insert(context));
break;
case "edit":
context.Response.Write(Update(context));
break;
case "del":
context.Response.Write(Delete(context));
break;
}
}
public string GetVendor()
{
JsonResponse _response = new JsonResponse();
System.Web.Script.Serialization.JavaScriptSerializer jSearializer =
new System.Web.Script.Serialization.JavaScriptSerializer();
try
{
System.Collections.Generic.List<vendor> _Vendor = _DbVendor.GetVendorDetails();
_response.IsSucess = true;
_response.Message = string.Empty;
_response.CallBack = CallBackMethodName;
_response.ResponseData = _Vendor;
}
catch (Exception ex)
{
_response.Message = ex.Message;
_response.IsSucess = false;
}
return jSearializer.Serialize(_response);
}
getVendorDetails()
功能在这里:
SqlConnection _con = new SqlConnection(ConfigurationManager.ConnectionStrings["junaidcrmConnectionString"].ConnectionString);
public List<VendorRep> GetVendorDetails()
{
try
{
List<VendorRep> _lstVendor = new List<VendorRep>();
VendorRep _Vendor = null;
if (_con.State != System.Data.ConnectionState.Open)
_con.Open();
SqlCommand _cmd = _con.CreateCommand();
_cmd.CommandText = "Select * From vendorrep";
SqlDataReader _Reader = _cmd.ExecuteReader();
while (_Reader.Read())
{
_Vendor = new VendorRep();
_Vendor.vendor_id = Convert.ToInt32(_Reader["vendor_id"]);
_Vendor.name = _Reader["name"].ToString();
_Vendor.phone = _Reader["phone"].ToString();
_Vendor.email = _Reader["email"].ToString();
_Vendor.jobtitle = _Reader["jobtitle"].ToString();
_Vendor.vendorrep_id =Convert.ToInt32(_Reader["adress"].ToString());
_lstVendor.Add(_Vendor);
}
return _lstVendor;
}
catch (Exception ex)
{
throw ex;
}
finally
{
if (_con.State != System.Data.ConnectionState.Closed)
_con.Close();
}
}
答案 0 :(得分:0)
您可以尝试更改这些:
jQuery("#jqgrid").jqGrid({
url:"/VendorDetailList.ashx",
mType: "json", // change to mtype and remove data:"{}" as you are using postData.
height: 'auto',
postData: {
Entity: function () {
return 'vendor';
}
},
来自此网址的和url:"/VendorDetailList.ashx",
返回一个有效的json,然后将填充您的jqgrid。
答案 1 :(得分:0)
代码中最重要的错误是使用dataType: "json"
而不是datatype: "json"
。需要删除包含未定义data: JSON.parse(result),
的{{1}}等选项。您不能将result
属性作为一列放置更多。我建议您在代码中加入key: true
回调(请参阅the answer)。