我有这个只有一个字段的表单,方法isValid()会一直处理它,好像每次提交它时它都是无效的,我一直在提交它应该是的文本
//form
class CategoryForm extends Form
{
public function __construct()
{
parent::__construct('category');
$this->setAttribute('method', 'post');
$this->add(array(
'name' => 'name',
'type' => 'text',
'options' => array('label' => 'Name',),
'required' => true,
'filters' => array(
array('name' => 'StripTags'),
array('name' => 'StringTrim'),
),
));
$this->add(array(
'name' => 'submit',
'attributes' => array(
'type' => 'submit',
'value' => 'Save',
'id' => 'submitbutton',
),
));
}
}
这将是错误的部分,我嘲笑,因为它有点工作,没有错误信息。
//validation clause at controller
$category = new Category;
$form = new CategoryForm();
$form->bind($category);
$request = $this->getRequest();
if ($request->isPost()) {
$form->setInputFilter($category->getInputFilter());
$form->setData($request->getPost());
if ($form->isValid()) {
$em = $this->getEntityManager();
$em->persist($category);
$em->flush();
$this->flashMessenger()->addSuccessMessage('category Saved');
return $this->redirect()->toRoute('category');
}
}
如果我将代码更改为此,则会保留数据
public function addAction()
{
$form = new CategoryForm();
$form->get('submit')->setValue('Add');
$request = $this->getRequest();
if ($request->isPost()) {
$category = new category();
$form->setInputFilter($category->getInputFilter());
$form->setData($request->getPost());
$form->isValid();
$category->exchangeArray($form->getData());
$em = $this->getEntityManager();
$em->persist($category);
$em->flush();
$this->flashMessenger()->addSuccessMessage('Category Saved');
return $this->redirect()->toRoute('category');
}
return new ViewModel(array(
'category' => $category,
'form' => $form
));
}
答案 0 :(得分:1)
您是否在验证之前将提交的值传递给表单?
我通常做这样的事情:
if ($this->_request->isPost() && $form->isValid($this->getRequest()->getPost())) {
...
Your save code here...
如果您这样做,请检查表单中是否出现了验证错误......
var_dump($form->getMessages());