Question

我有一个像两列一样简单的表名称，日期 - 这是一个包含＆＃34; Leads＆＃34;当用户从我们的网站查询时。

我需要生成一个过去10周的铅计数数据集吗？

预期输出为

Starting Week -- Count
==============
10     SUM(Last 10 weeks)
9    SUM(Starting from Week 9 for Last 10 weeks)
8    SUM(Starting from Week 8 for Last 10 weeks)

依此类推..它将有10行

它喜欢滑回一周，然后从那里算起最后10周

任何帮助？

Answer 1

您可以像这样对计数进行累积总和：

select DATEPART(week, [Date]) AS weekNo
  ,sum(count(*)) 
   over (order by DATEPART(week, [Date])
         rows unbounded preceding)
from tab
where ...
group by DATEPART(week, [Date])

Answer 2

完全窗口子句应该做什么。但是，您首先需要聚合数据：

select date, count(*) as cnt
from simple s
group by date;

假设您每天都有数据，那么您需要70天的计数。你可以通过总计70天的计数来得到它。那将是：

select date, count(*) as cnt,
       sum(count(*)) over
           (order by date rows between 69 preceding and current row)
from simple s
group by date;

这几天都有效。要在几周内完成此操作，您需要执行一些操作将天数转换为几周，然后更改窗口子句。您没有定义一周，但这可能接近您想要的一周：

select dateadd(day, 1 - datepart(weekday, date), date) as weekstart,
       count(*) as cnt,
       sum(count(*)) over
           (order by dateadd(day, 1 - datepart(weekday, date), date) rows between 9 preceding and current row)
from simple s
group by dateadd(day, 1 - datepart(weekday, date), date)
order by weekstart;

Answer 3

您可以使用以下查询：

SELECT Name,
       weekSlide + 1 AS weekSlide,
       COUNT(CASE WHEN weekDiff BETWEEN 0 AND 9 THEN 1 END) AS [Count]
FROM (
  SELECT Name,
         DATEPART(week, [Date]) AS weekNo,
         (x.c - DATEPART(week, [Date])) + 
         (YEAR(GETDATE()) - DATEPART(year, [Date])) * 52 - 
         y.weekSlide AS weekDiff,      
         y.weekSlide
  FROM mytable
  CROSS JOIN (SELECT DATEPART(week, GETDATE())) x(c) -- current week number
  CROSS JOIN (VALUES (0), (1), (2), (3), (4), (5), (6), (7), (8), (9)) AS y(weekSlide)) t
GROUP BY Name, weekSlide

weekSlide是周窗口的计数器，即包含从当前日期开始的最后10周的周窗口的0，从上周开始的周窗口1等等。

weekDiff是一个计算列，其中包含每个weekSlide的[日期]的偏移量。负偏移意味着超过周窗口的[日期]。

Demo here

Answer 4

我会用：

DECLARE @week INT, @end_date DATE
DECLARE @results AS TABLE (starting_week INT, count INT)

SET @week = 0
WHILE @week < 10
BEGIN
    SELECT @end_date = DATEADD(dd, @week * (-7), GETDATE())
    INSERT INTO @results
    SELECT (10 - @week),
           COUNT(1) FROM Leads
               WHERE Date BETWEEN (DATEADD(dd, -70, @end_date)) AND @end_date
    @week = @week + 1
END

SELECT * FROM @results

编辑：虽然Brian的问题（评论添加到您的初始问题中）是一个很好的问题 - 如果它不是＆＃34;从今天开始回滚＆＃34;，那么你＆＃39 ; d需要在@end_date的定义中添加另一行逻辑。

TSQL上次滚动10周的计数

4 个答案: