Question

我想使用TRANSLATE替换XMLAGG中使用的字符串中的无效XML字符，而不是嵌套REPLACE，因为需要替换大量字符：< / p>

select c.key,  
  cast( substr( xmlserialize( xmlagg( xmltext( concat( ' | ', 
    replace(replace(replace(replace(c.comment_text,chr(160),' '), chr(191),' '), chr(176),' '), chr(190),' ')
    --translate(c.comment_text, ' ', chr(160)||chr(176)||chr(190)||chr(191))
   ) ) order by c.comment_date desc ) as clob ), 3, 4000 ) as varchar2) as sum_comment
from comments c  
where c.comment_date > current_timestamp - 90
group by c.key

如果我在XMLAGG之外运行，我可以看到TRANSLATE和REPLACE都删除了无效字符，但在XMLAGG内我收到了错误我在使用TRANSLATE：

时试图避免

An illegal XML character "#xA0" was found in an SQL/XML expression or function argument that begins with string " | A".

TRANSLATE在XMLAGG

0 个答案: