当我添加一个新复选框时,旧复选框被设置为未选中(即使已选中它们)。我该如何解决?
这里有我的代码:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
<script type="text/javascript">
function zaza() {
document.body.innerHTML+=
'<input type="checkbox" name="vehicle" value="Bike"> I have a bike<br>';
}
</script>
</head>
<body>
<input type="checkbox" name="vehicle" value="Bike"> I have a bike<br>
<p onclick="zaza()">add</p>
</body>
</html>
答案 0 :(得分:3)
问题是你压倒身体html:
document.body.innerHTML+=
而是尝试将复选框附加到正文。
function zaza() {
var div = document.createElement('div');
div.innerHTML = '<input type="checkbox" name="vehicle" value="Bike"> I have a bike<br>';
document.body.appendChild(div);
}
p {
cursor: pointer;
}
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<p onclick="zaza()">add</p>
您也可以选择文档片段:
function zaza() {
var child = document.createDocumentFragment();
var tmp = document.createElement('input');
tmp.type = 'checkbox';
tmp.name = 'vehicle';
tmp.value = 'Bike';
child.appendChild(tmp);
child.appendChild(document.createTextNode('I have a bike'));
child.appendChild(document.createElement('br'));
document.body.appendChild(child);
}
p {
cursor: pointer;
}
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<p onclick="zaza()">add</p>
答案 1 :(得分:0)
您正在添加具有相同名称的复选框,您必须为每个复选框指定不同的名称
答案 2 :(得分:0)
你需要创建元素并附加在正文中
function zaza() {
var answer = document.createElement('input');
answer.setAttribute('type', 'checkbox');
answer.setAttribute('id', 'answer');
answer.setAttribute('value', 'a');
var answerLabel = document.createElement('label');
answerLabel.setAttribute('for', 'answer'); // this corresponds to the checkbox id
answerLabel.appendChild(answer);
answerLabel.appendChild(document.createTextNode(' I have a bike'));
document.body.appendChild(answerLabel);
linebreak = document.createElement("br");
answerLabel.appendChild(linebreak);
}