我正在使用JAX-WS API编写一个基本的Restful Web服务,您可以在其中提供城市名称,它会为您提供最低和最高温度以及其他一些信息。
我收到http://api.openweathermap.org/data/2.5/weather?q=singapore&mode=xml
的回复@WebServiceProvider
@ServiceMode(value = javax.xml.ws.Service.Mode.MESSAGE)
@BindingType(value = HTTPBinding.HTTP_BINDING)
public class RESTfulWeather implements Provider<Source> {
@Resource
protected WebServiceContext wsContext;
@Override
public Source invoke(Source request) {
MessageContext msg_cxt = wsContext.getMessageContext();
String httpMethod = (String) msg_cxt
.get(MessageContext.HTTP_REQUEST_METHOD);
System.out.println("Http Method : " + httpMethod);
if (httpMethod.equalsIgnoreCase("GET")) {
doGet(msg_cxt);
}
return null;
}
private void doGet(MessageContext msg_cxt) {
String query_string = (String) msg_cxt.get(MessageContext.QUERY_STRING);
System.out.println("Request String : " + query_string);
try {
URL url = new URL(
"http://api.openweathermap.org/data/2.5/weather?q=singapore&mode=xml");
HttpURLConnection urlConnection = (HttpURLConnection) url
.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.connect();
BufferedReader bReader = new BufferedReader(new InputStreamReader(
urlConnection.getInputStream()));
String line = null;
String text="";
while ((line = bReader.readLine()) != null) {
System.out.println(line);
text=text+line;
}
System.out.println(text);
} catch (Exception e) {
e.printStackTrace();
}
}
}
以下是发布商
public class WeatherPublisher {
public static void main(String[] args) {
System.out.println("Publishing Weather Service");
Endpoint.publish("http://127.0.0.1:8880/weather",new RESTfulWeather());
}
}
我确实在控制台中打印了xml,但是当我在浏览器中点击URL时并非如此。
如何将xml提供给浏览器,如何将XML响应从天气服务写入浏览器
以下是在控制台中打印的服务的响应,我也想在浏览器中使用
<?xml version="1.0" encoding="utf-8"?>
<current>
<city id="1880252" name="Singapore">
<coord lon="103.85" lat="1.29"/>
<country>SG</country>
<sun rise="2015-06-08T22:57:58" set="2015-06-09T11:09:41"/>
</city>
<temperature value="303.54" min="303.15" max="304.15" unit="kelvin"/>
<humidity value="66" unit="%"/>
<pressure value="1010" unit="hPa"/>
<wind>
<speed value="5.1" name="Gentle Breeze"/>
<direction value="260" code="W" name="West"/>
</wind>
<clouds value="75" name="broken clouds"/>
<visibility value="10000"/>
<precipitation mode="no"/>
<weather number="521" value="proximity shower rain" icon="09d"/>
<lastupdate value="2015-06-09T06:38:21"/>
</current>
答案 0 :(得分:0)
在servlet的doGet中尝试
import static java.lang.System.out;
PrintWriter out = response.getWriter();
response.getWriter().println("text");
out.println( "text");
其中响应是ServletResponse类型(或HttpServletResponse ingherited)。当尝试从另一个类调用它时,要么将整个ServletResponse或从getWriter()返回的PrinterWriter作为varibale传递。