让我们在我的目录中说我有五个文件。
档案:1,2,3,4,& 5
我有一个脚本会进行数学处理来比较两个文件,我想在目录中的每个文件上使用这个脚本,例如下面的例子。
比较文件1到2,3,4,& 5
比较文件2到3,4,& 5
比较文件3到4& 5
比较文件4到5
文件遵循此名称方案filename_V0001.txt
如何编写一个简单的bash脚本来执行此操作?
答案 0 :(得分:1)
<强> script_v1.sh:强>
#!/bin/bash
compare="/path/to/my/compare_tool"
for i in {1..5}; do
for j in $(seq $((i+1)) 5); do
echo "Comparing $i and $j"
compare filename_V000$i.txt filename_V000$j.txt > result_$i_$j.txt
done
done
<强> result_v1:强>
$ > bash script_v1.sh
Comparing 1 and 2
Comparing 1 and 3
Comparing 1 and 4
Comparing 1 and 5
Comparing 2 and 3
Comparing 2 and 4
Comparing 2 and 5
Comparing 3 and 4
Comparing 3 and 5
Comparing 4 and 5
$ >
<强> script_v2.sh:强>
#!/bin/bash
compare="/path/to/my/compare_tool"
for i in {1..100}; do
for j in $(seq $((i+1)) 100); do
fi="Filename_V$(printf "%04d" $i).txt"
fj="Filename_V$(printf "%04d" $j).txt"
if [[ -f "$fi" && -f "$fj" ]]; then
echo "Comparing $fi and $fj"
compare "$fi" "$fj" > result_$i_$j.txt
fi
done
done
<强> result_v2:强>
$ > bash script_v2.sh
Comparing Filename_V0001.txt and Filename_V0002.txt
...
Comparing Filename_V0001.txt and Filename_V0100.txt
Comparing Filename_V0002.txt and Filename_V0003.txt
...
Comparing Filename_V0002.txt and Filename_V0100.txt
Comparing Filename_V0003.txt and Filename_V0004.txt
...
Comparing Filename_V0099.txt and Filename_V0100.txt
$ >
假设:
- 从文件所在的路径调用脚本
答案 1 :(得分:0)
for a in *
do
start=0
for b in *
do
if [ "$start" = 1 ]
then
echo "Comparing $a with $b ..."
diff "$a" "$b"
elif [ "$a" = "$b" ]
then
start=1
fi
done
done
文件的任何名称方案当然都可以在glob模式中给出,例如: G。 for a in filename_V*.txt
。
答案 2 :(得分:0)
一种相当普遍的做法:
#!/bin/sh
for comp1; do
shift
for comp2; do
echo "Comparing '$comp1' with '$comp2'"
do_compare "$comp1" "$comp2"
done
done
然后您可以使用要比较的文件列表调用该脚本:
do_all_compares Filename_V*.txt
for x
相当于for x in "$@"
。该列表是在执行for
语句时计算的,因此在循环开始时发生的shift
只会影响内部比较的列表。