Question

我希望能够在列表中获取特定元素。但是，该列表包含在另一个列表中。原因是，我在一个属性文件中读取，其中键分配了多个值，用逗号分隔。我为每个键及其值创建一个列表，并将其添加到另一个列表中，该列表包含每个键及其值的多个列表。

# Menu properties file

menuEntryPoint=0
indent=\t\t\t
lines=---------------------------------------------------------

mainMenu=M a i n  M e n u
0.0=First Sub Menu, openMenu(1)
0.1=Second Sub Menu, openMenu(2)
0.2=Third Sub Menu, openMenu(3)

1=First Sub Menu
1.0=Execute this command, executeCommand(...)
1.1=Execute another command, executeCommand(...)
1.2=Execute other command, openMenu(A)

2=First Sub Menu
2.0=Execute this command, executeCommand(...)
2.1=Execute another command, executeCommand(...)
2.2=Execute other command, openMenu(A)

3=First Sub Menu
3.0=Execute this command, executeCommand(...)
3.1=Execute another command, executeCommand(...)
3.2=Execute other command, openMenu(A)

下面是我编写的用于将其打印到屏幕上的代码：

List<List<String>> menuProperties = new ArrayList<List<String>>();

public void configMenuDisplayProperties() throws IOException {

    Date date = new Date();
    Properties menuProp = new Properties();
    FileInputStream in = new FileInputStream("C:\\Test\\menu.properties");
    menuProp.load(in);

    //Create list of lists for properties
    menuProperties.add(getPropertyList(menuProp, "0"));
    menuProperties.add(getPropertyList(menuProp, "1"));
    menuProperties.add(getPropertyList(menuProp, "2"));
    menuProperties.add(getPropertyList(menuProp, "3"));

    System.out.println(date.toString() + "\t\t" + menuProp.getProperty("developmentArea") + "\n\n");
    System.out.println(menuProp.getProperty("indent") + menuProp.getProperty("mainMenu") + "\n");

        for (Enumeration<?> e = menuProp.propertyNames(); e.hasMoreElements(); ) {
            String name = (String)e.nextElement();
            String value = menuProp.getProperty(name);
            if (name.startsWith(menuProp.getProperty("menuEntryPoint"))) {
                System.out.println(menuProp.getProperty("indent") + name + "\t" + menuProp.getProperty(name));
            }
        }
    }

输出：

Mon Jun 08 13:39:43 EDT 2015        


        M a i n  M e n u

        0.2 Third Sub Menu, openMenu(C)
        0.1 Second Sub Menu, openMenu(2)
        0.0 First Sub Menu, openMenu(1)

我究竟如何打印出列表列表中某个键的某个值？我试图让我的输出看起来像这样，但我很难这样做。

Mon Jun 08 13:39:43 EDT 2015        


        M a i n  M e n u

        0.0 First Sub Menu
        0.1 Second Sub Menu
        0.2 Third Sub Menu

我尝试过以下

System.out.println(menuProp.getProperty("indent") + name + "\t" + menuProp.getProperty(name));

但是我得到你看到的第一个输出......非常感谢任何帮助。

Answer 1

考虑使用HashMap：

HashMap<String, ArrayList<String>> menuProperties = new HashMap();

您可以将您的属性存储在地图中（键，值列表）：

menuProperties.put("key", mylistofvalues);

您可以使用get()获取该属性：

ArrayList<String> tempList = menuProperties.get("mykey");

Answer 2

检查以下基于快速代码的解决方案，没有这样的基于API的解决方案可以满足您的要求。

如果您想获得所有第一个逗号值，请使用HashMap<String, String> indexedHashMap = getValueBashedOnIndex(hashMap, 1);，如果是第三个逗号值则使用HashMap<String, String> indexedHashMap = getValueBashedOnIndex(hashMap, 3);
基本上getValueBashedOnIndex的第二个参数是您想要的索引值。

@SuppressWarnings("rawtypes")
private static void readPropertiesFile() {
    ResourceBundle rb = ResourceBundle.getBundle("com.cgi.tmi.utils.test");
    Enumeration<String> keys = rb.getKeys();
    HashMap<String, String[]> hashMap = new HashMap<String, String[]>();
    while (keys.hasMoreElements()) {
        String key = keys.nextElement();
        String value = rb.getString(key);
        //System.out.println(key + ": " + value);
        hashMap.put(key, value.split(","));
    }
    HashMap<String, String> indexedHashMap = getValueBashedOnIndex(hashMap, 3);
    Iterator<Entry<String, String>> it = indexedHashMap.entrySet().iterator();
    while (it.hasNext()) {
        Map.Entry pair = (Map.Entry)it.next();
        System.out.println(pair.getKey() + " = " + pair.getValue());
    }
}

@SuppressWarnings("rawtypes")
private static HashMap<String, String> getValueBashedOnIndex(HashMap<String, String[]> hashMap, int i) {
    HashMap<String, String> indexedHashMap = new HashMap<String, String>();
    Iterator<Entry<String, String[]>> it = hashMap.entrySet().iterator();
    while (it.hasNext()) {
        Map.Entry pair = (Map.Entry)it.next();
        String[] strArr = (String[]) pair.getValue();
        String value = "";
        try {
            value = strArr[(i-1)];
        } catch (Exception e) {
        }
        indexedHashMap.put((String) pair.getKey(), value);
    }
    return indexedHashMap;
}

test.properties

menuEntryPoint=0
indent=\t\t\t
lines=---------------------------------------------------------

mainMenu=M a i n  M e n u
0.0=First Sub Menu, openMenu(1)
0.1=Second Sub Menu, openMenu(2)
0.2=Third Sub Menu, openMenu(3)

1=First Sub Menu
1.0=Execute this command, executeCommand(...)
1.1=Execute another command, executeCommand(...)
1.2=Execute other command, openMenu(A)

2=First Sub Menu
2.0=Execute this command, executeCommand(...)
2.1=Execute another command, executeCommand(...)
2.2=Execute other command, openMenu(A)

3=First Sub Menu
3.0=Execute this command, executeCommand(...)
3.1=Execute another command, executeCommand(...)
3.2=Execute other command, openMenu(A)

test=test1,test2,test3,test1

如何在列表列表中获取某个元素？

2 个答案: