Question

我需要帮助处理用于验证用户姓名的程序。必须有一定程度的宽容才能接受诸如连字符，空格和撇号之类的差异。目前我正在删除无用的字符来比较字符串，但是具有相同长度的完全不同的字符的名称正好是＆＃d; d。我如何检查名称是否起诉类似的字符。在无用的人被移除并一起捣碎之后。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
using System.Threading.Tasks;

namespace name_v
{
    class Program
{
    static void Main(string[] args)
    {
        Console.WriteLine("enter first name");
        string firstname = Console.ReadLine();
        Console.WriteLine("Enter 2nd name");
        string secondname = Console.ReadLine();

        if (firstname == secondname)
        {
            Console.WriteLine("Names are exactly the same");
            Console.ReadLine();
        }


        else
        {

            Console.WriteLine("press enter to Compare");
            Console.ReadLine();
            int numFirstName = firstname.Length;
            int numSecondName = secondname.Length;
            Console.WriteLine("# in 1st = " + numFirstName);
            Console.WriteLine("# in 2nd = " + numSecondName);
            Console.ReadLine();                                                                                                                                                   

            firstname = firstname.Replace(" ", "").Replace("-", "").Replace("'", "").Replace(".", "").ToUpper();
            secondname = secondname.Replace(" ", "").Replace("-", "").Replace("'", "").Replace(".", "").ToUpper();


            Console.WriteLine("Names to be compared as");
            Console.WriteLine(firstname);
            Console.WriteLine(secondname);
            numFirstName = firstname.Length;
            numSecondName = secondname.Length;
            Console.WriteLine("# in 1st = " + numFirstName);
            Console.WriteLine("# in 2nd = " + numSecondName);
            Console.ReadLine();

            int nameLengthDif = numFirstName - numSecondName;     

            if (firstname == secondname)
            {
                Console.WriteLine("Names are the same");
                Console.ReadLine();
            }
            else
            {
                Console.WriteLine("Names are not the same");
                Console.ReadLine();
                        if (nameLengthDif < 3)
                        {
                            Console.WriteLine("But Close enough");
                            Console.ReadLine();
                        }
                        else
                        {
                            Console.WriteLine("And not Close enough");
                            Console.ReadLine();
                        }
            }



        }

    }


}
}

Answer 1

@TestWell为确定角色差异提供了一个很好的解决方案，但我只想告诉你一个更好的方法来删除字符而不是串起.Replace（）一遍又一遍：

你可以在这个数组中添加/删除字符：

private char[] invalid = new char[] {' ','-','_','.'};
private static string cleanString(string input)
{    
   return new string(input.Where(x => !invalid.Contains(x)).ToArray()).ToLower();
}

用法：

 firstname = cleanString(firstname);

或作为扩展方法：

namespace CustomExtensions
{
 public static class StringExtension
 {
    private static char[] invalid = new char[] {' ','-','_','.'};
    public static string CleanString(this string y)
    {
      return new string(y.Where(x => !invalid.Contains(x)).ToArray()).ToLower();
    }
 }
}

用法：

firstname = firstname.CleanString();

Answer 2

怎么样

private static int GetDifferenceCount(string firstName, string lastName)
{
    int differences;
    string longestString = firstName;

    if (longestString.Length < lastName.Length)
        longestString = lastName;

    for (int i = 0; i < longestString.Length; i++)
    {
        try
        {
            if (firstName.Substring(i, 1) != lastName.Substring(i, 1))
                differences++;
        }
        catch
            differences++;
    }

    return differences;
}

返回不同字符的数量。然后你可以说

if (GetDifferenceCount(firstName, lastName) >= 2)
    // Do something

如果2个或更多字符不同，则完成操作。

Answer 3

尝试如下：

char[] firstName = firstName.ToCharArray();
char[] lastName = lastName.ToCharArray();
char[] res = firstName.Except(lastName).ToArray();
if(res.Length < 1)
{
  res = lastName.Except(firstName).ToArray();
}
nameLengthDif = res.Length

比较两个字符串的相似性进行名称验证

3 个答案: