数据库中的值不显示

时间:2015-06-08 15:55:54

标签: php mysql oop

我有一个显示所有数据的功能,在表格中。行返回的数量是正确的(基于编辑n删除按钮),但不显示该值。

public function viewAll()
    {
        $sql = "SELECT 'id','titleAnn','dateOpen','dateClose' FROM annoucement";
        $query = mysql_query($sql);
            while($row = mysql_fetch_array($query)) 
            {
                $id = $row['id'];
                $title = $row['titleAnn'];
                $dateOpen = $row['dateOpen'];
                $dateClose = $row['dateClose']; 
                echo '<tr>
                    <td><?php echo $title ?></td>   
                    <td><?php echo $dateOpen ?></td>   
                    <td><?php echo $dateClose ?></td>   
                    <td><a href="editAnnouncement.php?id=<?php echo $id;?>"><input type="button" name = "editAnn" value = "Edit" /></a></td>
                    <td><a href="deleteAnn.php?id=<?php echo $id;?>" onclick="confirm("Delete this announcement?");"><input type="button" name = "deleteAnn" value = "Delete"/></td>
                  </tr>';
            }
            $this->numrows= mysql_num_rows($query);
        }

按钮旁边只显示空格

2 个答案:

答案 0 :(得分:6)

你在回声中回应PHP ....如此连接和回声:

public function viewAll()
    {
        $sql = "SELECT 'id','titleAnn','dateOpen','dateClose' FROM annoucement";
        $query = mysql_query($sql);
            while($row = mysql_fetch_array($query)) 
            {
                $id = $row['id'];
                $title = $row['titleAnn'];
                $dateOpen = $row['dateOpen'];
                $dateClose = $row['dateClose']; 
                echo '<tr>
                    <td>'.$title.'</td>   
                    <td>'.$dateOpen.'</td>   
                    <td>'.$dateClose.'</td>   
                    <td><a href="editAnnouncement.php?id='.$id.'"><input type="button" name = "editAnn" value = "Edit" /></a></td>
                    <td><a href="deleteAnn.php?id='.$id.'" onclick="confirm("Delete this announcement?");"><input type="button" name = "deleteAnn" value = "Delete"/></td>
                  </tr>';
            }
            $this->numrows= mysql_num_rows($query);
        }

答案 1 :(得分:3)

public function viewAll()
{
    $sql = "SELECT 'id','titleAnn','dateOpen','dateClose' FROM annoucement";
    $query = mysql_query($sql);
        while($row = mysql_fetch_array($query)) 
        {
            $id = $row['id'];
            $title = $row['titleAnn'];
            $dateOpen = $row['dateOpen'];
            $dateClose = $row['dateClose']; 
            echo '<tr>
                <td>'. $title .'</td>   
                <td>'. $dateOpen .'</td>   
                <td><'. $dateClose .'</td>   
                <td><a href="editAnnouncement.php?id='. $id.'"><input type="button" name = "editAnn" value = "Edit" /></a></td>
                <td><a href="deleteAnn.php?id='. $id.'>" onclick="confirm("Delete this announcement?");"><input type="button" name = "deleteAnn" value = "Delete"/></td>
              </tr>';
        }
        $this->numrows= mysql_num_rows($query);
    }