Question

如果有人可以帮我进行单元测试，我真的很高兴 Visual Studio单元测试的业务逻辑..

我已经谷歌“ed”并检查了不同的单元测试方式，但我保留找到我不需要的控制器的单元测试..我是最多的有人可以帮助我知道如何对这种方法进行单元测试。

这是我的商务舱

public void AddConsultation(ConsultationView cv, int patientid)
{

    using (var deprepo = new ConsultationRepository())
    {
        if (cv.ConsultId == 0)
        {
            var curr = DateTime.Now;
            string date = curr.ToString("d");
            string  time= curr.ToString("t");
            var patient = da.Patients.ToList().Find(x => x.PatientId == patientid);

            Consultation _consultation = new Consultation
            {
              ConsultId = cv.ConsultId,
              ConsultDate = date,
              ConsultTime = time,
              illness = cv.illness,
              PresribedMed = cv.PresribedMed,
              Symptoms = cv.Symptoms,
              U_Id = patient.PatientId,
            };

            deprepo.Insert(_consultation);
        }
    }
}

这是我的存储库类

public class ConsultationRepository:IConsultationRepository
{
    private DataContext _datacontext = null;
    private readonly IRepository<Consultation> _clinicRepository;

    public ConsultationRepository()
    {
        _datacontext = new DataContext();
        _clinicRepository = new RepositoryService<Consultation>(_datacontext);

    }

    public Consultation GetById(int id)
    {
        return _clinicRepository.GetById(id);
    }

    public List<Consultation> GetAll()
    {
        return _clinicRepository.GetAll().ToList();
    }

    public void Insert(Consultation model)
    {
        _clinicRepository.Insert(model);
    }

    public void Update(Consultation model)
    {
        _clinicRepository.Update(model);
    }

    public void Delete(Consultation model)
    {
        _clinicRepository.Delete(model);
    }

    public IEnumerable<Consultation> Find(Func<Consultation, bool> predicate)
    {
        return _clinicRepository.Find(predicate).ToList();
    }

    public void Dispose()
    {
        _datacontext.Dispose();
        _datacontext = null;
    }
}

Answer 1

您可以让工厂为测试

创建不同的存储库

//Interface for a factory class
public interface IFactory
{
    IIConsultationRepository Create();
}

创建两个工厂，一个用于测试，一个用于生产

public class MyFactory : IFactory
{
    public IIConsultationRepository Create()
    {
        return new ConsultationRepository();
    }
}

public class MyTestFactory : IFactory
{
    public IIConsultationRepository Create()
    {
        return new ConsultationTestRpository();
    }
}

创建两个存储库。一个用于测试，一个用于生产

public class ConsultationTestRpository : IConsultationRepository
{
    //Your test repository. In this you skip the database.
    //This is just one simple example of doing it.
    Consultation _consultation;
    public Consultation GetById(int id)
    {
        return _consultation;
    }


    public void Insert(Consultation model)
    {
        _consultation = model;
    }

}

public class ConsultationRepository : IConsultationRepository
{
    //Your repository
}

将其用于制作

var obj = new TheConsultationClass(new MyFactory());

这是测试

[TestClass]
public class UnitTest1
{
    [TestMethod]
    public void TestMethod1()
    {
        var objForTesting = new TheConsultationClass(new MyTestFactory());

        var consultationView = new ConsultationView();



        objForTesting.AddConsultation(consultationView, 123);

        var consultation = objForTesting.GetById(...);

        Assert.AreEqual(123, consultation.U_Id );
    }
}

修改

我忘了展示如何使用工厂。将其作为参数发送到构造函数，然后调用Factory.Create（）

public class TheConsultationClass { public MyFactory Factory { get; set; } public TheConsultationClass(IFactory factory) { Factory = factory; } public void AddConsultation(ConsultationView cv, int patientid) { using (var deprepo = Factory.Create()) { if (cv.ConsultId == 0) { var curr = DateTime.Now; string date = curr.ToString("d"); string time = curr.ToString("t"); var patient = da.Patients.ToList().Find(x => x.PatientId == patientid); Consultation _consultation = new Consultation { ConsultId = cv.ConsultId, ConsultDate = date, ConsultTime = time, illness = cv.illness, PresribedMed = cv.PresribedMed, Symptoms = cv.Symptoms, U_Id = patient.PatientId, }; deprepo.Insert(_consultation); } } } }

Answer 2

如果您正在阅读测试控制器的示例并理解它们，那么测试正常的类和方法应该非常简单。它基本相同，但你可以更好地控制你的类结构。

目前，您的代码存在一些难以测试的问题。让我们看看你现有的代码：

public void AddConsultation(ConsultationView cv, int patientid)
{

下面一行创建一个新的ConsultantRepository。这很难模拟，这意味着很难检查是否正确调用了存储库。更好的方法是通过其构造函数将存储库或工厂注入类。如@AxdorphCoder所述，这可以手动滚动，或者你可以使用像CastleWindsor或Ninject这样的IOC容器为你做一些繁重的工作。

    using (var deprepo = new ConsultationRepository())
    {
        if (cv.ConsultId == 0)
        {

下一行引用DateTime.Now。同样，这可能很难测试。同样，如果您需要知道使用特定日期，最简单的解决方案是为日期注入工厂，或注入该日期。如果 准确无误，则需要在测试开始时存储时间，然后确认所用时间介于测试开始时间和时间之间测试断言。

var curr = DateTime.Now; string date = curr.ToString("d"); string time= curr.ToString("t");

下一行引用da。这并未在您提供的代码示例中的任何位置初始化。它看起来像是另一个存储库......在这种情况下，关于注入存储库的建议就是这样。顺便说一句，如果找不到病人会怎么样？

var patient = da.Patients.ToList().Find(x => x.PatientId == patientid); Consultation _consultation = new Consultation { ConsultId = cv.ConsultId, ConsultDate = date, ConsultTime = time, illness = cv.illness, PresribedMed = cv.PresribedMed, Symptoms = cv.Symptoms, U_Id = patient.PatientId, }; deprepo.Insert(_consultation); } } }

那么，您将如何测试AddConsultant方法？让我们假设您将关注AAA pattern for test arrangement。以下是您可能会写的一些测试：

如果已经设置了ConsultId，则不会更新验证存储库

Arrange - Setup mock repository - setup da.Patients to contain Patient with correct id - Create system under test injecting repository - Create view, with ConsultId <> 0 Act - Call sut.AddConsultation(view, somePationId) Assert - No methods called on injected repository

验证使用视图中的值创建的咨询

Arrange - Create View to pass, containing consultId = 0 - setup da.Patients to contain Patient with correct id Store datetime test started Create mock Repository and set it up to expect a call to insert Create system under test and Inject respository Act - Call sut.AddConsultation(view, somePationId) Assert - Assert Insert on respository was called with a consultation Assert each property of consulation has expected values from Arrange Assert consultation date is >= Arrange Date and <= Now

如果找不到患者，则验证AddConsultation失败

Arrange - Create View to pass, containing consultId = 0 - setup da.Patients, that doesn't contain Patient with correct id Create mock Repository and set it up to not expect call Create system under test and Inject respository Act - Call sut.AddConsultation(view, somePationId) Assert - Assert exception thrown with correct information (currently not done)

如何测试这个业务逻辑

2 个答案: