Question

我正在尝试在球拍中编写define-let宏，“保存”(let ((var value) ...) ...)的标题，即(var value) ...部分，并允许稍后重新使用它上。

以下代码按预期工作：

#lang racket

;; define-let allows saving the header part of a let, and re-use it later
(define-syntax (define-let stx1)
  (syntax-case stx1 ()
    [(_ name [var value] ...)
     #`(define-syntax (name stx2)
         (syntax-case stx2 ()
           [(_ . body)
            #`(let ([#,(datum->syntax stx2 'var) value] ...)
                . body)]))]))

;; Save the header (let ([x "works]) ...) in the macro foo
(define-let foo [x "works"])
;; Use the header, should have the same semantics as:
;; (let ([x "BAD"])
;;   (let ([x "works])
;;     (displayln x))
(let ([x "BAD"])
  (foo (displayln x))) ;; Displays "works".

问题是宏破坏了卫生：如下面的例子所示，由宏生成的y中声明的变量define-let应该是一个新的，未打开的符号，由于卫生，但它设法泄漏出宏，并且(displayln y)错误地访问它。

;; In the following macro, hygiene should make y unavailable
(define-syntax (hygiene-test stx)
  (syntax-case stx ()
    [(_ name val)
     #'(define-let name [y val])]))

;; Therefore, the y in the above macro shouldn't bind the y in (displayln y).
(hygiene-test bar "wrong")
(let ((y "okay"))
  (bar (displayln y))) ;; But it displays "wrong".

如何编写define-let宏以使其行为与第一个示例相同，但是当宏生成标识符时保留卫生，在第二个示例中给出"okay"？

Answer 1

遵循提示＆＃34;语法参数＆＃34;来自Chris，这是一个解决方案：

#lang racket
(require racket/stxparam
         (for-syntax syntax/strip-context))

(define-syntax (define-let stx1)
  (syntax-case stx1 ()
    [(_ name [var expr] ...)
     (with-syntax ([(value ...) (generate-temporaries #'(expr ...))])
       #`(begin
           (define-syntax-parameter var (syntax-rules ()))
           ...
           (define value expr)
           ...
           (define-syntax (name stx2)
             (syntax-case stx2 ()
               [(_ . body)
                (with-syntax ([body (replace-context #'stx1 #'body)])
                  #'(syntax-parameterize ([var (syntax-id-rules () [_ value])] ...)
                     . body))]))))]))

(define-let foo [x "works"])

(let ([x "BAD"])
  (foo (displayln x)))       ; => works

(let ([x "BAD"])
  (foo 
   (let ([x "still works"])
     (displayln x))))        ; => still works

更新

此解决方案通过了评论中的附加测试。新解决方案将身体的上下文转移到要绑定的变量。

#lang racket
(require (for-syntax syntax/strip-context))

(define-syntax (define-let stx1)
  (syntax-case stx1 ()
    [(_ name [var expr] ...)
     #`(begin
         (define-syntax (name stx2)
           (syntax-case stx2 ()
             [(_ . body)
              (with-syntax ([(var ...) (map (λ (v) (replace-context #'body v))
                                            (syntax->list #'(var ...)))])
                #'(let ([var expr] ...) 
                    . body))])))]))

(define-let foo [x "works"])

(let ([x "BAD"])
  (foo (displayln x)))       ; => works

(let ([x "BAD"])
  (foo 
   (let ([x "still works"])
     (displayln x))))        ; => still works


(let ([z "cool"]) 
  (foo (displayln z)))       ; => cool

编写一个`define-let`宏，带有卫生

1 个答案: