我正在开发一个测验项目并尝试将bool数组转换为字符串数组,以便我可以向用户显示他们的答案。我试图枚举问题数组,并提取所有用户的答案和正确的答案,并将它们附加到一个新的数组。
用户答案转到userAnswers
正确答案转到correctAnswers
然后它调用一个函数checkResults,它将检查用户错误或正确的答案数。
这是我被卡住的地方。我使用map函数来比较2个数组,然后给我一个名为answer的新数组。如果答案匹配,它将返回true,如果它们没有,它将返回false。我不完全确定如何将answer里面的结果转换为一个字符串数组以呈现给用户。
// My Arrays
class QuizQuestion {
let question: String!
let answer: Bool!
let explanation: String!
var usersAnswer: Bool?
init(question: String, answer: Bool, explanation: String) {
self.question = question
self.answer = answer
self.explanation = explanation
}
}
let questions = [
QuizQuestion(question: "Do I like coffee?", answer: true, explanation: "Because it's awesome!"),
QuizQuestion(question: "Is bacon god's gift to mankind?", answer: true, explanation: "Because it's awesome!"),
QuizQuestion(question: "Should I take a nap right now?", answer: true, explanation: "You gotta review some code!"),
]
var userAnswers: [Bool] = []
var correctAnswers: [Bool] = []
// Submit Functions
func checkResults() {
let answer = map(zip(correctAnswers, userAnswers)){$0.0 == $0.1}
var finalResults = answer.map({"The following answer is \($0)"})
}
@IBAction func submitAll(sender: UIButton) {
let hasAnsweredAllQuestions = questions.reduce(true) { (x, q) in x && (q.usersAnswer != nil) }
println("has user answered all questions?: \(hasAnsweredAllQuestions)")
for (index, _) in enumerate(questions) {
userAnswers.append(questions[index].usersAnswer!)
correctAnswers.append(questions[index].answer)
}
if correctAnswers.count == 3 {
checkResults()
}
}
答案 0 :(得分:1)
func checkResults() {
let answer = map(zip(correctAnswers, userAnswers)){
($0.0 == $0.1) ? "correct" : "wrong"
}
var finalResults = answer.map({"The following answer is \($0)"})
}
希望这有帮助
答案 1 :(得分:0)
如果您只想将bool“更改”为字符串,可以再次使用map()
:
let answer = [1,2,2]
let correct = [6,7,2]
func checkResults() {
let answers = map(zip(correct, answer)) { $0.0 == $0.1 }
let results = answers.map { $0 == true ? "You answered right!" : "Nope, wrong!" }
map(results) { println($0) }
}
打印出来:
Nope, wrong!
Nope, wrong!
You answered right!