当我试图在休眠状态下制作两个主键时,我陷入了困境

时间:2015-06-08 06:35:29

标签: java hibernate

我上课了

public class Attendance  implements Serializable
{
    private Integer id,userId;
    private Date date;
    private  OfficeTime officeTime;
    private Set<TimeSlice> timeSlices;
    public Attendance()
    {

    }
}

现在我尝试使用hibernate mapping composite-id

制作两个主键
 <hibernate-mapping>
          <class name="Attendance">
           <composite-id>
              <key-property name="id"><generator class="increment"/></key-property>
              <key-property name="date" />
          </composite-id>

          <property name="userId" />

          <set name="timeSlices" cascade="all" >
            <key column="attendanceId" />
            <one-to-many class="TimeSlice" />
          </set>

          <many-to-one name="officeTime" class="OfficeTime"
            column="office_id" unique="true" not-null="true"
            cascade="all" />

          </class>

          </hibernate-mapping>

虽然这样做我得到了错误元素类型“key-property”的内容必须匹配“(meta *,column *,type?)”。 如何设置两个主键,一个必须自动递增。提前谢谢。

1 个答案:

答案 0 :(得分:0)

您当前的配置不遵循为composite-id元素设置的架构。 以下是复合ID的架构文档:

<composite-id name="propertyName" class="ClassName" mapped="true|false" access="field|property|ClassName"> node="element-name|." <key-property name="propertyName" type="typename" column="column_name"/> <key-many-to-one name="propertyName class="ClassName" column="column_name"/> ...... </composite-id>

这是一个示例配置:

<composite-id>
            <key-many-to-one name="username" class="org.myclass.UserDB" column="user_name"/>
            <key-property name="role" type="string" column="role_name"/>
        </composite-id>      

此处的文档位于:https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/mapping.html#mapping-declaration-compositeid