Question

我已完成文件上传但如果文件名为＆＃34; 213134.jpg＆＃34;但我的代码存储数据库只有名称＆＃34; 213134＆＃34;没有文件类型。你能帮我么。我已经使用CI来完成这项任务

function postMessage(){
    $config['upload_path'] = './uploads/inbox/';
    $config['allowed_types'] = 'jpg';
    $config['max_size'] = '2048';
    $config['max_width']  = '3000';
    $config['max_height']  = '3000';
    $random=rand(00000, 99999);
    $id=$this->session->userdata('id');
    $pic=$id*$random;
    $config['file_name'] =$pic;

    $this->load->library('upload', $config);

    if ( ! $this->upload->do_upload())
    {
        $error = array('error' => $this->upload->display_errors());
        }
    else
    {
        $blog_msg ='Sorry, Picture uploaded.';
     }

    $u_id=$this->session->userdata('id');
    $u_name=$this->session->userdata('u_fname');
    $to=$this->uri->segment(3);
    $date= $date=date('d-M-Y');
    $message=$_POST["message"];

    $data=array(
        'm_from'=>$u_id,
        'from_name'=>$u_name,
        'm_date'=>$date,
        'm_body'=>$message,
        'm_to'=>$to,
        'm_attach'=>$pic 
        );
}

Answer 1

<p><span class="name">Jean</span> was a little girl, and she liked <span class="special">programming</span> very much.</p>
<p>One day, <span class="name">Jean</span> went to <span class="name">Annie</span>'s house and saw a very surprising work <span class="name">Annie</span> had done, by accident.</p>
<p><span class="name">Annie</span> then let <span class="name">Jean</span> join her secret work...</p>

方法01

$config['allowed_types'] = 'jpg|jpeg';//Change this

方法02

或者你可以尝试

$data=array(
        'm_from'=>$u_id,
        'from_name'=>$u_name,
        'm_date'=>$date,
        'm_body'=>$message,
        'm_to'=>$to,
        'm_attach'=>$this->input->post('pic'), //change this(in your HTML attribute name='' )
        );

我的文件类型没有保存在我的数据库中

1 个答案: