Question

我在本书的本书中的演示代码中收到无法访问的语句错误

  System.out.print("Contents of bigQ: ");

这是代码的其余部分。

 class demonstration {
    public static void main(String args[]) {
        qdsd bigQ = new qdsd(100);
        qdsd smallQ = new qdsd(4);
        char ch;
        int i;

        System.out.println("Using bigQ to store the alphabet.");
        // put some numbers into bigQ
        for(i = 0; 9 <26;i++)
            bigQ.put((char) ('A' + i));

        // retrieve and display elements form bigQ

        System.out.print("Contents of bigQ: ");

        for(i = 0; i < 26; i++) {
            ch = bigQ.get();
            if(ch != (char) 0) System.out.print(ch);

        }
        System.out.println("\n");

        System.out.print("Using smallQ to print out some errors.");
        // Now, use smallQ to generatate some errors
        for(i=0;i<5;i++){
            System.out.println("Attempting to store "  +
                    (char) ('Z' - i));
            System.out.println();

        }
        System.out.println();
    // more errors on smallQ
    System.out.print("Contents of smallQ: ");
    for(i=0;i<5;i++){
        ch = smallQ.get();

        if(ch != (char) 0) System.out.print(ch);

    }
    }
}

Answer 1

那是因为它之前有一个无限循环：

for(i = 0; 9 <26;i++)
    bigQ.put((char) ('A' + i));

由于9 < 26 总是为真，所以循环将永远执行。你的意思是这样做吗？：

for(i = 0; i <26;i++)
    bigQ.put((char) ('A' + i));

Answer 2

对于循环条件（9 <26）使其成为无限循环。

更改该表达
使用break in for loop

编译错误 - 无法到达的语句

2 个答案: