Question

我正在使用PromiseKit，并希望强制顺序下载JSON。 JSON的数量可能会改变。

我已阅读this关于链接的内容。如果我有3个固定数量的下载，那就没关系了。

但是，如果我想要按顺序下载更改的下载次数怎么办？

这是我的2个网址的代码。我想知道如何通过数组上的dateUrlArray[i]迭代来做到这一点？

 - (void)downloadJSONWithPromiseKitDateArray:(NSMutableArray *)dateUrlArray {
    [self.operationManager GET:dateUrlArray[0]
                    parameters:nil]
    .then(^(id responseObject, AFHTTPRequestOperation *operation) {
        NSDictionary *resultDictionary = (NSDictionary *) responseObject;
        Menu *menu = [JsonMapper mapMenuFromDictionary:resultDictionary];
        if (menu) {
            [[DataAccess instance] addMenuToRealm:menu];
        }
        return [self.operationManager GET:dateUrlArray[1]
                               parameters:nil];
    }).then(^(id responseObject, AFHTTPRequestOperation *operation) {
        NSDictionary *resultDictionary = (NSDictionary *) responseObject;

        Menu *menu = [JsonMapper mapMenuFromDictionary:resultDictionary];
        if (menu) {
            [[DataAccess instance] addMenuToRealm:menu];
        }
    })
    .catch(^(NSError *error) {
        dispatch_async(dispatch_get_main_queue(), ^{
            [self handleCatchwithError:error];
        });
    }).finally(^{
        dispatch_async(dispatch_get_main_queue(), ^{
            DDLogInfo(@".....finally");
        });
    });
}

Answer 1

您正在寻找的概念是then能够链接。你想在for循环中链接多个promises。

我的Objective-C真的很生疏 - 但它应该看起来像：

// create an array for the results
__block NSMutableArray *results = [NSMutableArray arrayWithCapacity:[urls count]];
// create an initial promise
PMKPromise *p = [PMKPromise promiseWithValue: nil]; // create empty promise
for (id url in urls) {
    // chain
    p = p.then(^{
        // chain the request and storate
        return [self.operationManager GET:url
                parameters:nil].then(^(id responseObject, AFHTTPRequestOperation *operation) {
              [results addObject:responseObject]; // reference to result
              return nil; 
        });
    });
}
p.then(^{
    // all results available here
});

Answer 2

对于我们这些寻找 Swift 2.3 解决方案的人来说：

import PromiseKit

extension Promise {
    static func resolveSequentially(promiseFns: [()->Promise<T>]) -> Promise<T>? {
        return promiseFns.reduce(nil) { (fn1: Promise<T>?, fn2: (()->Promise<T>)?) -> Promise<T>? in
            return fn1?.then({ (_) -> Promise<T> in
                return fn2!()
            }) ?? fn2!()
        }
    }
}

请注意，如果promises数组为空，则此函数返回nil。

使用示例

以下是如何按顺序上传附件数组的示例：

func uploadAttachments(attachments: [Attachment]) -> Promise<Void> {
    let promiseFns = attachments.map({ (attachment: Attachment) -> (()->Promise<Void>) in
        return {
            return self.uploadAttachment(attachment)
        }
    })
    return Promise.resolveSequentially(promiseFns)?.then({}) ?? Promise()
}

func uploadAttachment(attachment: Attachment) -> Promise<Void> {
    // Do the actual uploading
    return Promise()
}

Answer 3

感谢Vegard的回答，我重写了Swift 3：

extension Promise {
    static func resolveSequentially(promiseFns: [()->Promise<T>]) -> Promise<T>? {
        return promiseFns.reduce(nil) { (fn1: Promise<T>?, fn2: (()->Promise<T>)?) -> Promise<T>? in
            return fn1?.then{ (_) -> Promise<T> in
                return fn2!()
            } ?? fn2!()
        }
    }
}



/* Example */
func uploadAttachments(_ attachments: [Attachment]) -> Promise<Void> {
    let promiseFns = attachments.map({ (attachment: Attachment) -> (()->Promise<Void>) in
        return {
            return self. uploadAttachment(attachment)
        }
    })

    return Promise.resolveSequentially(promiseFns: promiseFns)?.then{Void -> Void in} ?? Promise { Void -> Void in }
}

使用PromiseKit强制顺序下载

3 个答案: