Question

我想要的是与项目相关联的所有 Industries 的列表。我可以获得的是使用关联表的每个项目的所有行业ID 。我无法弄清楚如何从这些ID返回每个 Industry-＆gt; Name 。

我的数据库中有三个表：projects，projects_industries和industries。＆＃39; projects_industries＆＃39;表格包含＆＃39; id＆＃39;，＆＃39; project_id＆＃39;和＆＃39; industries_id＆＃39;。

以下代码返回一个空白的html页面。感谢您的帮助/建议！

ProjectsController ：

public function show(Project $project){
....$projectsindustries = DB::table('projects_industries')->select('*')->where('projects_id', $project->id)->get();
....$industries = Industry::all();
....return view('projects.show', compact('project', 'projectsindustries', 'industries'));
}

BTW，我知道$ projectsindustries数据库查询工作

Blade View ：

@if($projectsindustries)
....<ul>
........@foreach($projectsindustries as $projectindustry)
............@foreach($industries as $industry)
................<li><a href="#">{{ $industry::where('id', '=', '$projectindustry->industries_id')->get()->name; }}</a></li> 
............@endforeach
........@endforeach
....</ul>
@else
....<p>no industries.</p>
@endif

Answer 1

以下是我最终解决问题的方法......

数据库表和字段保持不变

项目控制器

<?php namespace App\Http\Controllers;

use DB;
use App\Project;
use App\ProjectIndustry;
use App\Industry;
    public function show(Project $project)
    {
    $projectsindustries = ProjectIndustry::where('projects_id', '=', $project->id)
        ->join('industries', 'industries_id', '=', 'industries.id')->get();

    return view('projects.show', compact('project', 'projectsindustries'));
    }

项目模型

使用Illuminate \ Database \ Eloquent \ Model;

class Project扩展了Model {

public function industries() {
    return $this->belongsToMany('Industry', 'projects_industries', 'projects_id', 'industries_id');
}

项目行业模式

使用Illuminate \ Database \ Eloquent \ Model;

class ProjectIndustry扩展了Model {

protected $table = 'projects_industries';

public function project()
{
return $this->belongsTo('Project', 'id', 'projects_id');
}

public function industry()
{
return $this->hasMany('Industry', 'id', 'industries_id');
}

行业模式

<?php namespace App;

use Illuminate\Database\Eloquent\Model;

class Industry extends Model {

    public function project()
    {
    return $this->belongsTo('Project');
    }

}

项目视图 projects / show.blade.php

@if($projectsindustries)
<h3>Industries:</h3>
    <ul>
        @foreach($projectsindustries as $projectindustry)
            <li><a href="{{ route('industries.show', $projectindustry->slug) }}">{{ $projectindustry->name }}</a></li>
        @endforeach
    </ul>
@else
    <p>no industries.</p>
@endif

我希望这对某人有帮助。

Laravel 5，使用关联/数据透视表

1 个答案: