我创建了一个数据库,它保存了相同的名称,并且在db.i中也是null值,当我输入名称和其他值时,如果名称已经存在于数据库中,则显示Toast并且在Toast中显示该名称已经存在并且执行不保存值。所以当所有值为空时我按保存它显示吐司请插入信息。任何人都帮我解决这个问题。没有回复
</MultiTrigger.Conditions>
<MultiTrigger.EnterActions>
<BeginStoryboard >
<Storyboard >
<DoubleAnimation Storyboard.TargetProperty="Opacity"
From="0.7" To="0.2" Duration="0:0:0.3" BeginTime="0:0:5" />
</Storyboard>
</BeginStoryboard>
</MultiTrigger.EnterActions>
</MultiTrigger>
// 这是我的数据插入活动
< public class FoodDbHelper extends SQLiteOpenHelper {
private static final String DATABASE_NAME = "MY_Calorie_DISH.DB";
private static final int DATABASE_VERSION = 1;
private static final String CREATE_QUERY =
"CREATE TABLE "+ Food.NewDishInfo.TABLE_NAME+"("
+ Food.NewDishInfo.DISH_NAME+" TEXT NOT NULL,"
+ Food.NewDishInfo.DISH_QUANTITY+" TEXT NOT NULL,"
+ Food.NewDishInfo.DISH_CALORIE+" INTEGER NOT NULL,"
+ Food.NewDishInfo.DISH_FAT+" TEXT NOT NULL,"
+ Food.NewDishInfo.DISH_PROTEIN+" TEXT NOT NULL,"
+ Food.NewDishInfo.DISH_SUGAR+" TEXT NOT NULL,"
+ Food.NewDishInfo.DISH_VITAMINS+" TEXT NOT NULL);";
public FoodDbHelper(Context context)
{
super(context,DATABASE_NAME,null,DATABASE_VERSION);
Log.e("DATABASE OPERATION","Database created / opened...");
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL(CREATE_QUERY);
Log.e("DATABASE OPERATION","Table created...");
}
public void addInformations(String name ,String quantity, Integer calorie, String fat ,
String protein,String sugar,String vitamins, SQLiteDatabase db){
ContentValues contentValues = new ContentValues();
contentValues.put(Food.NewDishInfo.DISH_NAME,name);
contentValues.put(Food.NewDishInfo.DISH_QUANTITY,quantity);
contentValues.put(Food.NewDishInfo.DISH_CALORIE,calorie);
contentValues.put(Food.NewDishInfo.DISH_FAT,fat);
contentValues.put(Food.NewDishInfo.DISH_PROTEIN,protein);
contentValues.put(Food.NewDishInfo.DISH_SUGAR,sugar);
contentValues.put(Food.NewDishInfo.DISH_VITAMINS,vitamins);
db.insert(Food.NewDishInfo.TABLE_NAME, null, contentValues);
Log.e("DATABASE OPERATION","one row inserted...");
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
}
} >
//提前谢谢