Question

我有一个问题，我现在想要解决很长时间。

虽然SELECT和INSERT INTO查询一切正常，但我无法在phpMyAdmin中更新我的数据库

        <?php

        // Vérification de la validité des informations
        if (isset($_POST['name_last']) AND isset($_POST['name_first']) AND isset($_POST['email']) AND isset($_POST['school']) AND isset($_POST['phone_number']) AND isset($_POST['birth_date']))
        {
            // On rend inoffensives les balises HTML que le visiteur a pu rentrer
            $_POST['login'] = htmlspecialchars($_POST['login']);
            $_POST['name_last'] = htmlspecialchars($_POST['name_last']);
            $_POST['name_first'] = htmlspecialchars($_POST['name_first']);
            $_POST['email'] = htmlspecialchars($_POST['email']);
            $_POST['school'] = htmlspecialchars($_POST['school']);
            $_POST['phone_number'] = htmlspecialchars($_POST['phone_number']);
            $_POST['birth_date'] = htmlspecialchars($_POST['birth_date']);

            $login = $_POST['login'];
            $name_last = $_POST['name_last'];
            $name_first = $_POST['name_first'];
            $email = $_POST['email'];
            $school = $_POST['school'];
            $phone_number = $_POST['phone_number'];
            $birth_dateInput = $_POST['birth_date'];    
            $birth_date = DateTime::createFromFormat('d/m/Y', $birth_dateInput)->format('Y-m-d');

            if (!preg_match("#^[a-z0-9._-]+@[a-z0-9._-]{2,}\.[a-z]{2,4}$#", $_POST['email']))
            {
            echo 'L\'adresse ' . $_POST['email'] . ' n\'est pas valide, recommencez !';
            }

            else {


            // Insertion
            $req = $bdd->prepare('UPDATE member_student(email, name_last, name_first, school, phone_number, birth_date) SET(:email, :name_last, :name_first, :school, :phone_number, :birth_date) WHERE login = $login');
            $req->execute(array(
            'email' => $email,
            'name_last' => $name_last,
            'name_first' => $name_first,
            'school' => $school,
            'phone_number' => $phone_number,
            'birth_date' => $birth_date
            ));


            echo 'Vos changement ont été pris en compte et votre nouvelle école est ' . $school . "  " . $login . "  " . $email . "  " . $name_last . "  " . $name_first . "  " . $id . "  " . $birth_date;
            ?>

一切似乎都运行正常，没有错误返回，网站显示： “Vos changementontétéliveen compte et votrenouvelleécoleest...”

然而，phpMyAdmin中的数据库没有更新！你知道问题可能来自哪里吗？我已检查过每个变量，与数据库的连接工作得很好，所以我认为问题来自MySQL查询。

任何帮助都会非常感激：只要我无法使更新查询工作，我就会陷入困境！

Answer 1

替换此代码

$req->execute(array(
                `email` => $email,
                `name_last` => $name_last,
                `name_first` => $name_first,
                `school` => $school,
                `phone_number` => $phone_number,
                `birth_date` => $birth_date
                ));

在数据库字段中使用此符号

Answer 2

$req = $bdd->prepare('UPDATE member_student(email, name_last, name_first, school, phone_number, birth_date) 
                SET("'.$email.'", "'.$name_last.'", "'.$name_first.'", "'.$school.'", '.$school.', "'.$birth_date.'") WHERE login='.$login);

试试这种方式

Answer 3

改变这个：

$req = $bdd->prepare('UPDATE member_student(email, name_last, name_first, school, phone_number, birth_date) SET(:email, :name_last, :name_first, :school, :phone_number, :birth_date) WHERE login = $login');

有了这个：

$req = $bdd->prepare('UPDATE member_student SET email = :email, name_last = :name_last, name_first = :name_first, school = :school, phone_number = :phone_number, birth_date = :birth_date WHERE login = :login');

Answer 4

试试这真的有用

$ req = $ bdd-＆gt; prepare（＆＃39; UPDATE member_student SET email = ?, name_last = ?, name_first = ?, school = ?, phone_number = ?, birth_date =？登录=？＆＃39;）;

$ req-＆gt;执行（数组（$ email，$ name_last，$ name_first，$ school，$ phone_number，$ birth_date，$ login））;

php / Mysql：UPDATE查询不起作用（SELECT和INSERT INTO工作时）

4 个答案: