Question

我需要在javascript中编写一个函数，它在文本中查找字符串并打印文本中找到字符串的次数。这是我的代码，由于某种原因它不起作用....请帮助

var word = 'text',
    text = 'This is some wierd stupid text to show you the stupid text without meaning text just wierd text oh text stupid text without meaning.';

searchWord(word, text);

function searchWord(word, text) {
    switch (arguments.length) {
        case 1: console.log('Invalid input, please try again'); break;
        case 2: var array = text.split(' ');
            for (var i = 0; i < array.length; i++) {
                var count = 0;
                if (array[i] === word) {
                    count ++;
                }
            }
            console.log('Word ' + word + ' is repeated in the text ' + count + ' times');

    }
}

Answer 1

您的代码中存在一个小问题。你必须搬家

var count = 0;

在for循环之外

。

Answer 2

移动

  var count = 0;

在你的循环之外

Answer 3

您的count变量应该在for loop之外，否则每次进入循环时都会重置它。

function searchWord(word, text) {
    switch (arguments.length) {
        case 1: console.log('Invalid input, please try again'); break;
        case 2: var array = text.split(' ');
            var count = 0;//Place it here.
            for (var i = 0; i < array.length; i++) {

                if (array[i] === word) {
                    count ++;
                }
            }
            console.log('Word ' + word + ' is repeated in the text ' + count + ' times');

    }
}

Answer 4

您可以使用正则表达式来计算出现次数

var word = 'text',
    text = 'This is some wierd stupid text to show you the stupid text without meaning text just wierd text oh text stupid text without meaning.';

searchWord(word, text);

function searchWord(word, text) {
    var re = new RegExp(""+text+"", "g");
    var count = (text.match(/text/g) || []).length;
    console.log('Word ' + word + ' is repeated in the text ' + count + ' times');
}

Answer 5

已经回答，但这是获得计数的简短版本：

function getWordCount(word, text) {
     if(arguments.length === 0) return;

     var count = 0;
     text.split(" ").forEach(function(val) {
          if(val === word) count++;
     });
}

Answer 6

一个简单的单行解决方案，没有循环或RegExp

这一行解决方案似乎有效。请注意，它会在句子的头部和尾部附加一个空格，以便在末尾捕获匹配的单词。这也可以使用纯RegExp来完成，但它不会是一行......我喜欢简单的解决方案。

return (' ' + text.toLowerCase() + ' ').split( ' ' + word.toLowerCase() + ' ' ).length - 1;

重构原始代码，我们可以消除10个无关的行和循环：

function searchWord(word, text) {
  return (' ' + text.toLowerCase() + ' ').split( ' ' + word.toLowerCase() + ' ' ).length - 1;
}

var word = 'text',
    text = 'This is some wierd stupid text to show you the stupid text without meaning text just wierd text oh text stupid text without meaning.';

console.log('Word ' + word + ' is repeated in the text ' + searchWord(word,text) + ' times');

在数组Javascript中搜索ot字符串

6 个答案:

一个简单的单行解决方案，没有循环或RegExp