Question

我在将MySQL数据库表打印到PHP代码时遇到问题。我希望MySQL表作为实际表格打印在我的网站上，而不仅仅是数据库值。我所做的一切似乎都不起作用，我已经看过类似的问题，但仍无法使其发挥作用。

Answer 1

    $result = mysql_query("SELECT * FROM {$table}");
    if (!$result) {
        die("Query to show fields from table failed");
    }

    $fields_num = mysql_num_fields($result);


    echo "<table border='1'><tr>";
    // printing table headers
    for($i=0; $i<$fields_num; $i++)
    {
        $field = mysql_fetch_field($result);
        echo "<td>{$field->name}</td>";
    }
    echo "</tr>\n";
    // printing table rows
    while($row = mysql_fetch_row($result))
    {
        echo "<tr>";


        foreach($row as $cell)
            echo "<td>$cell</td>";

        echo "</tr>\n";
    }
    echo "</table>";

Answer 2

您必须使用SELECT语句，以便从数据库中检索数据并将其保存在变量中。获得数据后，可以使用for循环打印表格。

Answer 3

在你的html表单中放置一个名为fetch的提交按钮，如下所示

  <form method="post" action="yourphpfilename.php">
 <input type="submit" name ="fetch" value="FETCH DATA" />
 </form>

并在您的php代码中插入此代码并进行配置。

  if(isset($_POST['fetch']))
  {
    // Connect to database server
   $con=mysqli_connect("localhost", "root", "") or die (mysqli_error ());

   // Select database
   mysqli_select_db($con,"databasename") or die(mysqli_error());

 // SQL query
$strSQL = "SELECT * FROM tablename ;

// Execute the query (the recordset $rs contains the result)
$rs = mysqli_query($con,$strSQL);


  print "
  <table border=\"5\" cellpadding=\"5\" cellspacing=\"0\" style=\"border-  collapse: collapse\" bordercolor=\"#808080\" width=\"100&#37;\"    id=\"AutoNumber2\" bgcolor=\"#C0C0C0\">
   <tr>
   <td width=100>ID:</td> 
  <td width=100>First Name</td> 
  <td width=100>Last Name</td> 
  <td width=100>Email</td> 
  <td width=100>User Name</td>
  <td width=100>Password</td> 
  <td width=100>Date Of Birth</td> 
  <td width=100>Gender</td> 
  </tr>"; 
 while($row = mysqli_fetch_array($rs))
 { 
print "<tr>"; 
print "<td>" . $row['id'] . "</td>"; 
print "<td>" . $row['fname'] . "</td>"; 
print "<td>" . $row['lname'] . "</td>"; 
print "<td>" . $row['Email'] . "</td>";
print "<td>" . $row['uname'] . "</td>";
print "<td>" . $row['password'] . "</td>";
print "<td>" . $row['dob'] . "</td>";
print "<td>" . $row['gender'] . "</td>"; 
print "</tr>"; 
} 
print "</table>"; 

  }
 }

Answer 4

试试这个：

    <?php
        $sql = "SELECT id, firstname, lastname FROM MyGuests";
        $result = $conn->query($sql);

        if ($result->num_rows > 0) {
            echo "<table><tr><th>ID</th><th>Name</th></tr>";
            // output data of each row
            while($row = $result->fetch_assoc()) {
                echo "<tr><td>".$row["id"]."</td><td>".$row["firstname"]." ".$row["lastname"]."</td></tr>";
            }
            echo "</table>";
        } else {
            echo "0 results";
        }
        $conn->close();
    ?>

在php中打印MySQL表（简单）

4 个答案: