我可能太累了,看了一个小错误,但是这段代码不会在我的数据库中输入任何信息。
$sql = "INSERT INTO TABLE_NAME (UPC, Description, Make, Model, SNLocation, IMEI_MEID, Resetting, Notes, Image)
VALUES ($UPC, $Desc, $Make, $Model, $SNLocation, $IMEI_MEID, $Resetting, $Notes, $Image)";
mysqli_query($con, $sql) or die(mysqli_error($sql));
有人可以帮我检查一下这是否存在语法问题?
答案 0 :(得分:1)
因为你有错误
$sql = "INSERT INTO TABLE_NAME (UPC, Description, Make, Model, SNLocation, IMEI_MEID, Resetting, Notes, Image)
VALUES ('$UPC', '$Desc', '$Make', '$Model', '$SNLocation', '$IMEI_MEID', '$Resetting', '$Notes', '$Image')";
从Notes, Image)]
<-----
移除] ,并且需要引用值
答案 1 :(得分:1)
您需要删除]
并用单引号('
)括起字符串值:
$sql = "INSERT INTO TABLE_NAME
(UPC, Description, Make, Model,
SNLocation, IMEI_MEID, Resetting, Notes, Image)] <-- Here -->
VALUES ($UPC, $Desc, $Make, $Model, $SNLocation, $IMEI_MEID, $Resetting, $Notes, $Image)";
mysqli_query($con, $sql) or die(mysqli_error($sql));