$subSpecialties = $this->_db->get('users_subspecialties',array('user_id', '=', $this->_data->id));
print_r($subSpecialties);
foreach ($subSpecialties as $subSpecialty) {
echo "THIS CODE IS GENERATED FROM INSIDE FOREACH";
}
第一行从我的users_subspecialties
表
然后我使用print_r
检查找到的记录。
输出如下所示:
DB Object ( [_pdo:DB:private] => PDO Object ( ) [_query:DB:private]
=> PDOStatement Object ( [queryString] => SELECT * FROM
users_subspecialties WHERE user_id = ? ) [_error:DB:private] =>
[_results:DB:private] => Array ( [0] => stdClass Object ( [user_id]
=> 1 [subspecialty_id] => 2 ) [1] => stdClass Object ( [user_id] => 1
[subspecialty_id] => 3 ) ) [_count:DB:private] => 2 )
最后一行是我for-each
;它应该运行,因为您可以通过print_r
输出找到2条记录,但它赢得了echo
内部代码。
有人可以告诉我看起来是什么问题吗?提前谢谢。
答案 0 :(得分:1)
如果这个回答是对象,你可以这样:
foreach ($subSpecialties as $subSpecialty) {
echo $subSpecialty->user_id;
echo '<br/>';
echo $subSpecialty->subspecialty_id;
}
如果此响应是数组,那么
foreach ($subSpecialties as $subSpecialty) {
echo $subSpecialty[user_id];
echo '<br/>';
echo $subSpecialty[subspecialty_id];
}
答案 1 :(得分:1)
$subSpecialties = $this->_db->get('users_subspecialties',array('user_id', '=', $this->_data->id));
print_r($subSpecialties);
foreach ($subSpecialties->results() as $subSpecialty) {
echo "THIS CODE IS GENERATED FROM INSIDE FOREACH";
}