Question

我有以下MySQL查询。

    Scanner scannerLines = new Scanner(file)) {
    int lineNum = 0;
    while (scannerLines.hasNextLine()) {
        String line = scannerLines.nextLine();
        if (line.contains(" alle ")) {
            String nextLine = scannerLines.nextLine();
            Pattern pattern = 
                    Pattern.compile("\\s\\d\\d\\s");

            Matcher matcher = 
                    pattern.matcher(nextLine);  

           while(matcher.find()){                        
             System.out.println(matcher.group());
           }

        }

    }

输出在这里：

SELECT h.hostname
     , c.name
     , d.cim_item
     , t.datastatus
     , DATEDIFF(NOW(), s.time) 
  FROM plugin_sw_vmware_healthmon_hosts h
  JOIN 
     ( SELECT clientid
            , locationid
            , hostname
            , MAX(scantime) Time
         FROM labtech.plugin_sw_vmware_healthmon_scans
        GROUP  
           BY clientid
            , locationid
            , hostname
     ) s
    ON h.clientid = s.clientid
   AND h.locationid = s.locationid
   AND h.hostname = s.hostname
  JOIN clients c
    ON c.clientid = h.clientid 
  JOIN plugin_sw_vmware_healthmon_cimdata d
    ON d.clientid = h.clientid
   AND d.locationid = h.locationid 
   AND d.hostname = h.hostname 
  JOIN plugin_sw_vmware_healthmon_types t
    ON t.datavalue = d.cim_value 
   AND t.datatype = h.vender 
 WHERE d.cim_item LIKE '%critical array%' 
 ORDER  
    BY c.name;

我想要做的是将Corp1的所有结果合并为一行，将Corp2合并到第二行，以便它看起来像这样：

ESXi Host Name Client Name Item Type      RAID Status Last Updated (days ago)
192.14.13.2    Corp1        disk array 1  Good                              0
192.14.13.2    Corp1        disk array 2  Good                              0
192.14.13.2    Corp1        disk array 3  Good                              0
192.14.13.2    Corp1        disk array 4  Good                              0
192.14.13.2    Corp1        drisk array 5 Good                              0
192.16.11.5    Corp 2       disk array 1  Good                              4
192.16.11.5    Corp 2       disk array 2  Good                              4
192.16.11.5    Corp 2       disk array 3  Good                              4
192.16.11.5    Corp 2       disk array 4  Good                              4
192.16.11.5    Corp 2       drisk array 5 Good                              4

如何在我的查询中执行此操作？

Answer 1

您可以尝试GROUP_CONCAT，如下所示：

UIImageView* iv = [[UIImageView alloc] initWithImage:nil highlightedImage:im];
iv.userInteractionEnabled = NO;
[cell addSubview: iv];

MySQL查询组合行

1 个答案: